A circle can have perpendicular bisector lines by means of its diameter.
A circle cannot form a perpendicular bisector.
Draw a line from any part on the outside of a circle to the exact center of the circle. * * * * * That is fine if you know where the center is but not much use if you are just given a circle and do not know where the exact centre is. In this case: Draw a chord - a straight line joining any two points on the circumference of the circle. Then draw the perpendicular bisector of the chord. Draw another chord and its perpendicular bisector. The two perpendicular bisectors will meet at the centre.
A circle is a shape that has no particular direction. There is, therefore, no particular direction for anything to be perpendicular to. To that extent, this question is nonsense.Every diameter of a circle bisects it, so just draw any line through its centre!
Draw a cord through the circle (a line through the circle, but not too close to where you imagine the center to be). With construction techniques, find the perpendicular at the center point of the cord, and draw the perpendicular. Do the same thing again starting with a different cord, and the two perpendiculars will intersect at the center of the circle.
Yes, the perpendicular bisector of a cord is the shortest distance from the centre of a circle to the cord.
A circle can have perpendicular bisector lines by means of its diameter.
A circle cannot form a perpendicular bisector.
Yes. The perpendicular bisector of a chord forms a radius when extended to the centre of the circle and a diameter when extended beyond the centre to the opposite point on the circumference.
The perpendicular bisector of ANY chord of the circle goes through the center. Each side of a triangle mentioned would be a chord of the circle therefore it is true that the perpendicular bisectors of each side intersect at the center.
A circle cannot form a perpendicular bisector.
You have points A, B, and C. Using a compass and straight edge, find a perpendicular bisector of AB (that is, a line that is perpendicular to AB and intersects AB at the midpoint of AB. Next, find a perpendicular bisector of BC. The two lines you found will meet at the center of the circle.
Perpendicular bisector lines intersect at right angles
-- Draw any two random chords of the circle. -- Construct the perpendicular bisector of each chord. -- The perpendicular bisectors intersect at the center of the circle. All of this can be done with a compass, an unmarked straight-edge, and a pencil.
Draw a line from any part on the outside of a circle to the exact center of the circle. * * * * * That is fine if you know where the center is but not much use if you are just given a circle and do not know where the exact centre is. In this case: Draw a chord - a straight line joining any two points on the circumference of the circle. Then draw the perpendicular bisector of the chord. Draw another chord and its perpendicular bisector. The two perpendicular bisectors will meet at the centre.
A circle is a shape that has no particular direction. There is, therefore, no particular direction for anything to be perpendicular to. To that extent, this question is nonsense.Every diameter of a circle bisects it, so just draw any line through its centre!
Perpendicular bisector.