No. Irrational Numbers are denser.
No, the irrationals are more dense.
It belongs to the set ofrational numbers,decimal fractions,improper fractions (in decimal form),real numbers,complex numbers,quaternions.
is a set of real numbers with the property that any number that lies between two numbers is the set.
Every integers are real numbers.more precisely, integers are the subset of R, the set of real numbers.They are whole numbers with no decimals or fractions
Your question is ill-posed. I have not come across a comparison dense-denser-densest. The term "dense" is a topological property of a set: A set A is dense in a set B, if for all y in B, there is an open set O of B, such that O and A have nonempty intersection. The rational numbers are indeed dense in the set of real numbers with the standard topology. An open set containing a real number contains always a rational number. Another way of saying it is that every real number can be approximated to any precision by rational numbers. There are denser sets, if you are willing to consider more elements. Suppose you construct a set consisting of the rational numbers plus all algebraic numbers. The set of algebraic numbers is also countable, but adding them, makes it obviously easier to approximate real numbers. Can you perhaps construct a set less dense than the set of rational numbers? Suppose we take the set of rational numbers without the element 0. Is this set still dense in the real numbers? Yes, because 0 can be approximated by 1/n, n>1. In fact, you can remove finite number of rational numbers from the set of rational numbers and the resulting set will still be dense in the set of the real numbers.
Every integers are real numbers.more precisely, integers are the subset of R, the set of real numbers.They are whole numbers with no decimals or fractions
Only if they are fractions in their simplified form.
No. Every fraction has a decimal expression but not every decimal has a fractional (rational) equivalent. There are infinitely many fractions: the cardinality of the set of fractions is Ào (Aleph-null). If the set of decimals is considers equivalent to the set of real numbers, then the cardinality of the set is 2À0 !
real numbers
Yes. Both the commutative property of addition, and the commutative property of multiplication, works:* For integers * For rational numbers (i.e., fractions) * For any real numbers * For complex numbers
In a certain sense, the set of complex numbers is "larger" than the set of real numbers, since the set of real numbers is a proper subset of it.
All rational numbers can be expressed as fractions whereas irrational numbers can't be expressed as fractions.