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It is a pure imaginary number.

Since (a+bi)-(a-bi) = 2bi, it is a pure imaginary number (it has no real component).

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Q: Is the difference of a complex number and its conjugate a real imaginary or pure imaginary number?
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Related questions

Is the difference of a complex number and it's conjugate an imaginary number?

Yes. By definition, the complex conjugate of a+bi is a-bi and a+bi - (a - bi)= 2bi which is imaginary (or 0)


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When a complex number is multiplied by its conjugate, the product is a real number and the imaginary number disappears.


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For a complex number (a + bi), its conjugate is (a - bi). If the number is graphically plotted on the Complex Plane as [a,b], where the Real number is the horizontal component and Imaginary is vertical component, the Complex Conjugate is the point which is reflected across the real (horizontal) axis.


Find the complex conjugate of 14 plus 12i?

To find the complex conjugate of a number, change the sign in front of the imaginary part. Thus, the complex conjugate of 14 + 12i is simply 14 - 12i.


Define conjugate number?

A conjugate number refers to a complex number having both the imaginary and real parts of opposite signs and equal magnitude.


What is self conjugate of complex number?

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