Aamir jamal;
All real numbers are complex numbers with 0 as its imaginary part.A real number is
self-conjugate.
e.g;a+0i
self conjugate =a-0i i=iota
Since the imaginary portion of a real number is zero, the complex conjugate of a real number is the same number.
Yes. By definition, the complex conjugate of a+bi is a-bi and a+bi - (a - bi)= 2bi which is imaginary (or 0)
To get the conjugate simply reverse the sign of the complex part. Thus conj of 7-4i is 7+4i
"Conjugate" usually means that in one of two parts, the sign is changed - as in a complex conjugate. If the second part is missing, the conjugate is the same as the original number - in this case, 100.
The complex conjugate of 2-3i is 2+3i.
Graphically, the conjugate of a complex number is its reflection on the real axis.
When a complex number is multiplied by its conjugate, the product is a real number and the imaginary number disappears.
The conjugate is 7-5i
The conjugate is 7 - 3i is 7 + 3i.
Assuming that the question is in the context of complex number, the product of any real number with itself (its square) is a real number.
For a complex number (a + bi), its conjugate is (a - bi). If the number is graphically plotted on the Complex Plane as [a,b], where the Real number is the horizontal component and Imaginary is vertical component, the Complex Conjugate is the point which is reflected across the real (horizontal) axis.
The concept of conjugate is usually used in complex numbers. If your complex number is a + bi, then its conjugate is a - bi.
Yes they do, complex conjugate only flips the sign of the imaginary part.
-6i-8
If you have a complex function in the form "a+ib", the (complex) conjugate is "a-ib". "Conjugate" is usually a function that the original function must be multiplied by to achieve a real number.
Since the imaginary portion of a real number is zero, the complex conjugate of a real number is the same number.
Yes. By definition, the complex conjugate of a+bi is a-bi and a+bi - (a - bi)= 2bi which is imaginary (or 0)