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To be divisible by 2 the number must be even, that is its last digit must be 2, 4, 6, 8, or 0; the last digit of 432 is 2 which is one of {2, 4, 6, 8, 0} so 432 is even and divisible by 2.

To be divisible by 3 sum the digits of the number; if this sum is divisible by 3 then the original number is divisible by 3. The test can be repeated on the sum until a single digit remains, in which case if this single digit is 3, 6, or 9 then the original number is divisible by 3; For 432: 4 + 3 + 2 = 9 which is one of {3, 6, 9} so 432 is divisible by 3.

To be divisible by 5 the last digit must be a 0 or 5; the last digit of 432 is a 2 which is not 0 nor 5, so 432 is not divisible by 5.

To be divisible by 6, the number must be divisible by both 2 and 3; these have been tested above and found to be true, so 432 is divisible by 6.

To be divisible by 9 sum the digits of the number; if this sum is divisible by 9 then the original number is divisible by 9. The test can be repeated on the sum until a single digit remains, in which case if this single digit is 9 then the original number is divisible by 9; For 432: 4 + 3 + 2 = 9 which is 9 so 432 is divisible by 9

To be divisible by 10 the last digit must be a 0; the last digit of 432 is a 2 which is not 0, so 432 is not divisible by 10.

432 is divisible by 2, 3, 6 and 9, but not divisible by 5 nor 10.

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Q: Is the number 432 divisible by 2 3 5 6 9 10?

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Not evenly. You get 43.2 as the answer. To be divisible by 10, the last digit must be 0 The last digit of 432 is 2 which is not 0, so it is not divisible by 10.

None of them. 432 is divisible by 2, 3, 4, 6, 8 and 9.

No, but 432 is divisible by 2 and 3.

Yes, it is divisible by 2, 3 and 9, but is not exactly divisible by 5 or 10.

432 is divisible by 2 and 3.

432 is divisible evenly by both 2 and 3

The only such number which satisfies this criteria is 432.

No.

Yes, 432 is divisible by 2. Hope I helped you! ;) Good luck on your test or quiz!!

Because two goes into 432 evenly: 432 ÷ 2 = 216

Numbers divisible by 9 have the sum of their digits equal to 9 or a multiple of 9. A number divisible by 2 is an even number. If a 3 digit number is 42n then n can only be 3 if the number is divisible by 9 and 423 is not within the specified range. If a 3 digit number is 43n then n must be 2 for it to be divisible by 9.. The number is thus 432 and this is even and so divisible by 2. If the 3 digit number is 44n then n must be 1 and 441 is odd and not divisible by 2. The only valid solution is 432.

432, 468

All except 5

If you want to know if a number is prime or composite, begin by looking at it. The last digit of 432 is even; that means that 432 is divisible by two, so it can't be prime. Look again. Add up the digits of 432. 4 + 3 + 2 = 9. 9 is divisible by 3, so 432 is divisible by 3. Not prime. In fact 432 is about as composite as you can get. It is 2 X 2 X 2 X 2 X 3 X 3 X 3.

Yes.

1, 2, 3, 4, 6, 8, 9, 12, 16, 18, 24, 27, 36, 48, 54, 72, 108, 144, 216, 432

Any number that is divisible by 10 is an even number and hence divisible by 2 also. It can also be stated that because 10 is divisible by 2, all numbers divisble by 10 are also divisible by 2.

Because 10 is divisible by both 2 and 5

Yes, by 1, 2, 3, 4, 6, 8, 9, 12, 16, 18, 24, 27, 36, 48, 54, 72, 108, 144, 216, 432

There are no numbers that satisfy this. If a number is divisible by both 2 and 5, then it must also be divisible by 10.

12

432/2 = 216432/4 = 108432/6 = 72432/8 = 54432/9 = 48432/12 = 36432/ 16 = 27432/18 = 24

yes 432/2 = 216 432/3 = 144 432/4 = 108 432/6 = 72 432/8 = 54 432/9 = 48

10 is divisible by both 5 and 2, as are any multiples of 10.

No. (Example.....10 / 2 = 5, but 10 / 4 = 2.5)