No, but 432 is divisible by 2 and 3.
To be divisible by 2 the number must be even, that is its last digit must be 2, 4, 6, 8, or 0; the last digit of 432 is 2 which is one of {2, 4, 6, 8, 0} so 432 is even and divisible by 2. To be divisible by 3 sum the digits of the number; if this sum is divisible by 3 then the original number is divisible by 3. The test can be repeated on the sum until a single digit remains, in which case if this single digit is 3, 6, or 9 then the original number is divisible by 3; For 432: 4 + 3 + 2 = 9 which is one of {3, 6, 9} so 432 is divisible by 3. To be divisible by 5 the last digit must be a 0 or 5; the last digit of 432 is a 2 which is not 0 nor 5, so 432 is not divisible by 5. To be divisible by 6, the number must be divisible by both 2 and 3; these have been tested above and found to be true, so 432 is divisible by 6. To be divisible by 9 sum the digits of the number; if this sum is divisible by 9 then the original number is divisible by 9. The test can be repeated on the sum until a single digit remains, in which case if this single digit is 9 then the original number is divisible by 9; For 432: 4 + 3 + 2 = 9 which is 9 so 432 is divisible by 9 To be divisible by 10 the last digit must be a 0; the last digit of 432 is a 2 which is not 0, so 432 is not divisible by 10. 432 is divisible by 2, 3, 6 and 9, but not divisible by 5 nor 10.
432 ÷ 3 = 144
432 is divisible by 3 and 4 because the quotients are whole numbers. 432/3 = 144 432/4 = 108
Yes 3 x 144 = 432.
432 is divisible evenly by both 2 and 3
None of them. 432 is divisible by 2, 3, 4, 6, 8 and 9.
432/3 = 144 432/4 = 108 432 is divisible by both 3 and 4.
If you want to know if a number is prime or composite, begin by looking at it. The last digit of 432 is even; that means that 432 is divisible by two, so it can't be prime. Look again. Add up the digits of 432. 4 + 3 + 2 = 9. 9 is divisible by 3, so 432 is divisible by 3. Not prime. In fact 432 is about as composite as you can get. It is 2 X 2 X 2 X 2 X 3 X 3 X 3.
Yes, it is divisible by 2, 3 and 9, but is not exactly divisible by 5 or 10.
yes 432/2 = 216 432/3 = 144 432/4 = 108 432/6 = 72 432/8 = 54 432/9 = 48
Numbers divisible by 9 have the sum of their digits equal to 9 or a multiple of 9. A number divisible by 2 is an even number. If a 3 digit number is 42n then n can only be 3 if the number is divisible by 9 and 423 is not within the specified range. If a 3 digit number is 43n then n must be 2 for it to be divisible by 9.. The number is thus 432 and this is even and so divisible by 2. If the 3 digit number is 44n then n must be 1 and 441 is odd and not divisible by 2. The only valid solution is 432.
Yes, by 1, 2, 3, 4, 6, 8, 9, 12, 16, 18, 24, 27, 36, 48, 54, 72, 108, 144, 216, 432
The prime factorization of 432 is 2 * 2 * 2 * 2 * 3 * 3 * 3 or 2^4 * 3^3
The prime factors of 432 are 2, 2, 2, 2, 3, 3, and 3.
The GCF of 432 and 522 is 9. The prime factorization of 432 is 2*2*2*2*3*3*3 The prime factorization of 522 is 2*3*3*29 So the GCF of 432 and 522 is 3*3 is 9.
There's a trick you can use: A number is divisible by 3 if and only if the sum of its digits is divisible by 3. Here 2+4+5+2 = 13. Is 13 divisible by 3? You decide.