Yes. 90 / 6 = 15
90 is.LCM(5, 6, 9) = 90.
90 (90/6= 15; 90/5= 19)
30, 60, 90...
90
It is 90.
LCM(6, 9, 10) = 90
To find a number between 80 and 100 that is divisible by both 5 and 6, we need to find the least common multiple (LCM) of 5 and 6, which is 30. We then look for a multiple of 30 between 80 and 100, which is 90. Therefore, the number 90 between 80 and 100 is divisible by both 5 and 6.
The anwer is 90 ,90 divided 6 is 15 and 90 divided by 5 is 18.
2,3,5,6,9,10. Not by 4.
90
There are no odd multiples of 6. If a number is a multiple of 6 then it is divisible by 6. If a number is divisible by 6 it is also divisible by 2 and 3 (see the fundamental theorem of arithmetic). If a number is divisible by 2 then it is even by definition. Therefore any number divisible by 6 is even.
Hmm...perhaps you should be doing your own work, but here's my answer: Yes to both. 90 ends in 0 and is less than or greater than 5, so it is divisible by 5. 30 is divisible by 6, and 90 is divisible by 30, so 90 is also divisible by 6.