Yes. 90 / 6 = 15
90 is.LCM(5, 6, 9) = 90.
90 (90/6= 15; 90/5= 19)
To find a number between 80 and 100 that is divisible by both 5 and 6, we need to find the least common multiple (LCM) of 5 and 6, which is 30. We then look for a multiple of 30 between 80 and 100, which is 90. Therefore, the number 90 between 80 and 100 is divisible by both 5 and 6.
30, 60, 90...
90
It is 90.
LCM(6, 9, 10) = 90
The anwer is 90 ,90 divided 6 is 15 and 90 divided by 5 is 18.
2,3,5,6,9,10. Not by 4.
90
There are no odd multiples of 6. If a number is a multiple of 6 then it is divisible by 6. If a number is divisible by 6 it is also divisible by 2 and 3 (see the fundamental theorem of arithmetic). If a number is divisible by 2 then it is even by definition. Therefore any number divisible by 6 is even.
To determine if the number 23,456,910 is divisible by 90, it must be divisible by both 9 and 10. A number is divisible by 10 if it ends in 0, which 23,456,910 does. To check for divisibility by 9, the sum of its digits (2 + 3 + 4 + 5 + 6 + 9 + 1 + 0 = 30) must be divisible by 9, which it is not. Therefore, 23,456,910 is not divisible by 90.