There can be no such number. If it is divisible by 5 and 6it must be divisible by 6.
99990
99990
No,because 45 is not divisible by both 2 and 3. In order for a number to be divisible by 6 it has to be divisible by both 2 and 3.
90 (90/6= 15; 90/5= 19)
30.
There are no numbers that satisfy this. If a number is divisible by both 2 and 5, then it must also be divisible by 10.
Multiply 6 x 5 6x10 6x15 and so on if you can get it by multiplying by 6 and 5 both then your good
There can be no such number. If it is divisible by 5 and 6it must be divisible by 6.
Since 5232 is divisible by both 2 and 3, it is divisible by 6.A number must be divisible by both 2 and 3 to be divisible by 6.The number 5232 is even, so it is divisible by 2.If you add the individual digits in the number (5+2+3+2=12) you get a number that is divisible by 3, meaning the original number (5232) is also divisible by 3.
Any number that is divisible by both 2 and 3 is divisible by 6.
99990
To find a number between 80 and 100 that is divisible by both 5 and 6, we need to find the least common multiple (LCM) of 5 and 6, which is 30. We then look for a multiple of 30 between 80 and 100, which is 90. Therefore, the number 90 between 80 and 100 is divisible by both 5 and 6.
99990
The smallest number that is divisible by 5, 6, and 7 is 210.
No,because 45 is not divisible by both 2 and 3. In order for a number to be divisible by 6 it has to be divisible by both 2 and 3.
90 (90/6= 15; 90/5= 19)