It depends on the base, but for either e or 10, it is irrational.
Yes. Take any rational number p. Let a = any number that is not a power of 10, so that log(a) is irrational. and let b = p/log(a). log(a) is irrational so 1/log(a) must be irrational. That is, both log(a) and log(b) are irrational. But log(a)*log(b) = log(a)*[p/log(a)] = p which is rational. In the above case all logs are to base 10, but any other base can be used.
36 is a rational number
Irrational numbers are precisely those real numbers that cannot be represented as terminating or repeating decimals. Log 216 = 2.334453751 terminates and is therefore not irrational.
No. An irrational number cannot be expressed as a/b where a and b are integers, b not zero. 18 = 18/1 = 36/2 = -36/-2 etc.
The square of 36 is 1,296 ... rational.The square root of 36 is 6 ... also rational.
Yes. Take any rational number p. Let a = any number that is not a power of 10, so that log(a) is irrational. and let b = p/log(a). log(a) is irrational so 1/log(a) must be irrational. That is, both log(a) and log(b) are irrational. But log(a)*log(b) = log(a)*[p/log(a)] = p which is rational. In the above case all logs are to base 10, but any other base can be used.
The square root of negative 36 is an imaginary number and therefore not an irrational number. For a number to be irrational it must first be real.
Irrational numbers are precisely those real numbers that cannot be represented as terminating or repeating decimals. Log 216 = 2.334453751 terminates and is therefore not irrational.
36 is a rational number
yes
no
If you mean 36 minus 25 then the square root of 11 is an irrational number
No because the square root of 36 is 6 which is a rational number
The square roots of 36 are ±6, therefore, sqrt(36) is a rational number.
Yes. The square root of any number that is not a perfect square (like 9 or 36) is irrational.
They are both rational.
No. An irrational number cannot be expressed as a/b where a and b are integers, b not zero. 18 = 18/1 = 36/2 = -36/-2 etc.