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If the 'ratio' (length/width) of one rectangle is the same number as (length/width) of the other one, then the two rectangles are similar.
These are not similar rectangles so there is no obvious candidate for the ratio. Is it ratio of lengths (sides, perimeter, diameter), or ratio of area?
The width is half the length: The perimeter is twice the length plus twice the width. If the perimeter is 3 times the length, twice the width must be the length.
The factor pairs are the length and width of the rectangles.
There are infinitely many such rectangles.
If the 'ratio' (length/width) of one rectangle is the same number as (length/width) of the other one, then the two rectangles are similar.
These are not similar rectangles so there is no obvious candidate for the ratio. Is it ratio of lengths (sides, perimeter, diameter), or ratio of area?
The width is half the length: The perimeter is twice the length plus twice the width. If the perimeter is 3 times the length, twice the width must be the length.
yes, all rectangles are in fact congruent. they're all congruent because its a ratio of sizes. if u have a rectangle with a length of 5 and a width of 2.5, and an another rectangle with a length of 10 and a width of 5, u have a ratio of sixes. the ratio would be 1:2. hope it helps (:
The factor pairs are the length and width of the rectangles.
There are infinitely many such rectangles.
If you are trying to find the ratio of the lengths of two similar rectangles, divide the length of one side of one rectangle by the corresponding side length of the other rectangle. To find the ratio between their volumes, divide the volume of one rectangle by the volume the other rectangle. To find volume, multiply the width of the rectangle by the length of the rectangle.
The answer is 576cm.
Length x Width
If two similar rectangles have the widths 16m and 14cm what is the ratio of the perimiters?
The expression is L - 3.
Divide the width by the length: width -------- height