It is an irrational number.
irrational
Yes. For example, the square root of 3 (an irrational number) times the square root of 2(an irrational number) gets you the square root of 6(an irrational number)
No. The square root of 6 is irrational.
It is known that the square root of an integer is either an integer or irrational. If we square root2 root3 we get 6. The square root of 6 is irrational. Therefore, root2 root3 is irrational.
6 times the square root of 6
Whatever number times the same number... hard 2 explain Example: 6•6 is 36 so the squared root of 36 is 6
⁴√1296 = 4√(36)2 = √36 = ±6
It is irrational. * The square root of any positive integer, except of a perfect square, is irrational. * The product of an irrational number and a rational number (except zero) is irrational.
Root 6 is an irrational [real] number.
Yes.
No because the square root of 36 is 6 which is a rational number