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Q: Is the square root of 0 a real number?

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The square root of a real number is not always positive. The square root of any positive number is positive, the square root of zero is zero (not positive), and the square root of a negative number is complex (i.e. neither positive nor negative). The square root of 16 = -4 or 4. The square root of 0 = 0 The square root of -16 = -4i or 4i

The square root of 1 is 1.The square root of 0 is 0.

The square root of -1 is not a real number like -2.5, 0, or 5. Instead, it is and imaginary number, i, and i = the square root of -1. The answer is imaginary because you can never take a real number, square it, and get a negative number. However, i^2 = -1.

a is a real number since we use just letters to represent real numbers. if a > 0, then its square root is also a real number, so it has two square roots, one positive and one negative. Be careful when you use the radical sign, because it is looking only for the principal square root of a, which is the positive one. if a < 0, then its square root is an imaginary number.

The square root of any negative number is imaginary. No integers nearby.

There is no answer to this problem unless x is 0. For the suare root of 98x to be a real number, x has to be positive or zero. For the square root of -147x to be a real number, x has to be negative or zero. Seeing has x has to fit both requirements, the problem has an answer only if x is zero.

Yes, if the number whose square root we are taking is greater than 0. Only if you try to take the square root of a negative number will you get back an imaginary number. Square roots are often irrational, but that's different from real versus imaginary.

The square root of both 0 and 1 equals the square of 0 and 1

X is greater than 5. If X were equal to 5, X-5 would be 0 which has no real square root. If X were 4, X-5 would be -1 which has no real square root, and so on.

BeginRead:aSet Sqt=pow(a,1/2)If (a

The square of any real number is non-negative. So no real number can have a negative square. Consequently, a negative number cannot have a real square root. If the discriminant is less than zero, the quadratic equation requires the square root of that negative value, which cannot be real and so must be imaginary.

0

The square root of 0 would be 0 because 0 * 0 = 0

"0" And if you think about it, zero times zero is still zero. Zero times anything is zero, so this doesn't have an exception when you do the reverse to find the square root.The square root of a number (n) is a number that when multiplied by itself (squared) results in the original number (n). Therefore, the square root of 0 must be 0 because 0 x 0 = 0.

probably x would be negative. This is because the square root of a negative number is not a real number (no real number squared can be negative). ory is 0. any number divided by 0 = infinity. and undefined is another way of saying infinity.

The square root of 0 = 0. Rational is defined as a value that can be expressed as a quotient of integers. For example, 0/1 = 0 and 0/2 = 0. Although 0/0 is undefined, the former examples are still true. Therefore, the square root of 0 is rational. For your knowledge, the square root of any number is rational, except for negative numbers, which are irrational. This is because two identical integers cannot be multiplied to produce a negative integer. For instance, the square root of 25 is 5 because 5x5 = 25. However, the square root of -25 has no real roots because neither -5x-5 nor 5x5 = -25.

Sqrt(0) = 0 so the answer is 0.

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It is the equation inside the square root of the Quadratic FormulaIf > 0 there is a solutionIf < 0 there is no solutionBecause you can not calculate the Square Root of a Negative Number

The square root of a positive whole number, N, is a number which, when multiplied by itself equals N. If N = 0 then the square root is also 0. If N is greater than 0 there will be two such numbers: one positive and the other its negative equivalent. If N is a perfect square the square roots will, themselves, be whole numbers. Otherwise, they will be irrational numbers. If N is a whole number less than 0 then there are no real square roots. Although there are square roots in the complex field, the fact that you ask this question is indicative that you are not yet ready to tackle complex numbers.

Any number greater than 0 has two square roots, a positive square root and a corresponding negative square root. Rounded to two decimal places, the square roots of 134 are Â±11.58.

The square root of 49 is 7 and it is a natural number because natural numbers are from 0-infinity

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If x is 0, the square root is 0 also.

/*Java program to find out square root of a given number * without using any Built-In Functions */ public class SquareRootDemo2 { public static void main(String[] args) { //Number for which square root is to be found double number = -12; //This method finds out the square root findSquareRoot(number); } /*This method finds out the square root without using any built-in functions and displays it */ public static void findSquareRoot(double number) { boolean isPositiveNumber = true; double g1; //if the number given is a 0 if(number==0) { System.out.println("Square root of "+number+" = "+0); } //If the number given is a -ve number else if(number<0) { number=-number; isPositiveNumber = false; } //Proceeding to find out square root of the number double squareRoot = number/2; do { g1=squareRoot; squareRoot = (g1 + (number/g1))/2; } while((g1-squareRoot)!=0); //Displays square root in the case of a positive number if(isPositiveNumber) { System.out.println("Square roots of "+number+" are "); System.out.println("+"+squareRoot); System.out.println("-"+squareRoot); } //Displays square root in the case of a -ve number else { System.out.println("Square roots of -"+number+" are "); System.out.println("+"+squareRoot+" i"); System.out.println("-"+squareRoot+" i"); } } }