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Well, first let's define a "real number." A real number is any number that's not imaginary. It can be rational or irrational. The square root of 7 is 2.64575131... and it goes on forever. This means it cannot be written as a simple fraction. We can give an estimate of the square root of 7 in a fraction form, but this is not the exact result. So, the square root of 7 is a irrational number.

Since a real number can be irrational or rational, yes, the square root of 7 is a real number.

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Q: Is the square root of seven a real number?

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The square root of seven is a real number, but it is not a whole number.

There is no real number [square] root of a negative number. There is a real cube root and a real fiftth root etc, but root, by itself, implies square root.

The square root of 0 is 0, which is a real number.

The square root of any positive real number (as in this case) is a real number. (Such square roots are usually irrational.)The square root of a negative real number, such as the square root of -15, is an imaginary, and therefore also a complex, number.

Of course, not only can it be a real number but it is a real number. When you take the square root times itself, the result is a number that is real.

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the square root of 25 is 5

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The square root of 8 is irrational and real.

It is not the square of a whole number; but it is the square of a real number. If you calculate the square root of 23, you will get a real number. That real number times itself will equal 23. But the square root will not be a simple whole number. It will have an endless decimal fraction.

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