Set up an augmented matrix and use Gaussian elimination to solve the system:
3 2 | 15
6 4 | 30
~2 * R1 -> R1
6 4 | 30
6 4 | 30
~ -1 * R1 + R2-> R2
6 4 | 30
0 0 | 0
~ 1/6 * R1 -> R1
1 2/3 | 5
0 0 | 0
We can conclude two things from this:
1) The system is consistent, because there are no "bad" rows (no row reduces down to 0 ... | 1)
2) There is a free variable.
The solution to the system is x + 2/3y = 5, where 'y' is free.
A consistent system.
Which system of inequalities has no solution?A.y > 3x - 1y < 3x - 3B.y > 3x + 3y < 3x + 7C.y > -1y < 2y > 2x - 3re...
If you mean: 3x-4y = 19 and 3x-6y = 15 Then: x = 9 and y = 2
the system of equations 3x-6y=20 and 2x-4y =3 is?Well its inconsistent.
3x+5y=48 5y=48-3x-3x+5y=12 -3x+(48-3x)=12-6x=-36x=65y=48-3(6)5y=30y=6(6,6)
If this is a system you have Y expressed in terms of X. 2(3X - 5) - X = 0 6X - 10 - X = 0 5X = 10 X = 2 --------------find Y Y = 3(2) - 5 Y = 6 - 5 Y = 1 ----------------check in first equation 2(1) - 2 = 0 2 - 2 = 0 0 = 0 both check and system is consistent
The system is simultaneous linear equations
3x
x+8y=28 -3x+5y=3
3x + 3x + 3x = 3* (3x) = 9x
If you mean: 3x+2y = 6 and -4x+5y = 15 then it works out as x = 0 and y = 3
The system is inconsistent because there is no solution, i.e., no ordered pair, that satisfies both equations. You can see that this will be the case by seeing that their graphs have the same slope (2) but different y-intercepts (2 and 3/4 respectively). So the lines are parallel and will not intersect.