The 4th derivative is very useful in the process of trying to findthe maximum and minimum points of the 3rdderivative.
Oh, dude, the third derivative of ln(x) is -2/(x^3). But like, who really needs to know that, right? I mean, unless you're planning on impressing your calculus teacher or something. Just remember, math is like a puzzle, except no one actually wants to put it together.
1 divided by x to the third power equals x to the negative third. The derivative of x to the negative third is minus three x to the negative fourth.
First derivative of displacement with respect to time = velocity. Second derivative of displacement with respect to time = acceleration. Third derivative of displacement with respect to time = jerk.
Another name ? You haven't given us one yet. The third derivative of displacement with respect to time is "jerk".
Can you be more specific.
in case of derivative w.r.t time first derivative with a variable x gives velocity second derivative gives acceleration thid derivative gives jerk
The first derivative is m and the second is 0 so the third is also 0.
If the second derivative of a function is zero, then the function has a constant slope, and that function is linear. Therefore, any point that belongs to that function lies on a line.
You are supposed to use the chain rule for this. First step: derivative of root of sin2x is (1 / (2 root of sin 2x)) times the derivative of sin 2x. Second step: derivative of sin 2x is cos 2x times the derivative of 2x. Third step: derivative of 2x is 2. Finally, you need to multiply all the parts together.
The purpose of finding a derivative is to find the instantaneous rate of change. In addition, taking the derivative is used in integration by parts.
This is an example of a sentence using the word derivative. The teacher liked it when the student used the derivative of the trash words