Wiki User
∙ 14y agoin case of derivative w.r.t time
first derivative with a variable x gives velocity
second derivative gives acceleration
thid derivative gives jerk
Wiki User
∙ 14y agoI'm not sure about the respect to time, but the equation for velocity is the first derivative of the equation of time (w/ respect to distance) and acceleration is the second derivative. I'm sorry, I don't think I properly answered your question, but this information should be correct. . :)
1st derivative is the rate of change. If, for example, you start driving your car from home, and x is a measure of distance from your home , then d/dx is your speed. In that same example, the 2nd derivative would be your acceleration (change of speed). And the 3rd derivative would be your change in acceleration (also known as 'jerk').
Average Speed = Total Distance/Total Time.Instantaneous Speed = Derivative of Distance with respect to Time.
To find the rate of change. Velocity, for example, is the rate of change of distance - in a specified direction. Acceleration is the rate of change of velocity.
Using different instruction methods and learning activities to teach a concept. Ideas may be using flash cards to learn vocabulary, using a deck of playing cards to call on students to answer questions, using internet web sites as an instructional aid, etc.
I'm not sure about the respect to time, but the equation for velocity is the first derivative of the equation of time (w/ respect to distance) and acceleration is the second derivative. I'm sorry, I don't think I properly answered your question, but this information should be correct. . :)
1st derivative is the rate of change. If, for example, you start driving your car from home, and x is a measure of distance from your home , then d/dx is your speed. In that same example, the 2nd derivative would be your acceleration (change of speed). And the 3rd derivative would be your change in acceleration (also known as 'jerk').
First derivative of distance with respect to time.
Average Speed = Total Distance/Total Time.Instantaneous Speed = Derivative of Distance with respect to Time.
If you are only given total distance and total time you cannot. If you are given distance as a function of time, then the first derivative of distance with respect to time, ds/dt, gives the velocity. Evaluate this function at t = 0 for initial velocity. The second derivative, d2s/dt2 gives the acceleration as a function of time.
acceleration/decceleration it is the second derivative of a displacement vs time function
Work.
velocity is 1st derivative of distance with respect to time acceleration is 2nd derivative of distance with respect to time dx/dt = velocity = 3t^2 dv/dt = acceleration = 6t
Basically "speed" tells you how fast something moves. It is defined as a distance divided by a time (more precisely, in the case of variable speed, the derivative of distance with respect to time).
Velocity is the derivative of position with respect to time (v = dx/dt). Acceleration is the derivative of velocity with respect to time (a = dv/dt) and therefore the second derivative of position with respect to time (a = d2v/dt2). A derivative basically refers to the "rate of change" - graphically, it is the slope on a curve.
In Simple motion, there is no force being applied. The moving object moves in a straight line with constant velocity. In acceleration, there is a force applied. The object's velocity is changing. The first derivative of acceleration is velocity. The first derivative of velocity is distance. (Derivative is a calculus thing.)
The distance from the fulcrum to the point of application of the effort force is known as the effort arm. It determines the mechanical advantage of a lever system, with longer effort arms providing greater leverage.