Yes: 88 = 2 x 2 x 2 x 11 OR 23 x 11
The exponent of 88 refers to the power to which a base number must be raised to equal 88. In this case, we need to find the exponent in an exponential expression like ( b^x = 88 ). To determine the exponent, we can express 88 as a product of prime factors, which is 2^3 * 11. Therefore, the exponent of 88 is 3 when expressed in terms of its prime factorization.
No
88 44,2 22,2,2 11,2,2,2
The prime factors of 88 are 2 and 11.
The greatest common factor of 77 and 88 is 11, and it is also the greatest prime factor.
3,888 = 24 x 35
The Prime Factors of 88 are 2, 11
58 = 2 x 29. No prime power exists since there are no duplicate prime numbers in the prime factorization.
The prime factorization of 144 is 2^4 * 3^2. The prime factor is 2 and the exponent is 4.
Assume this problem deals with multiples of the numbers. The objective is vague, but I'm pretty sure of what is asked here.If we want to find the gcd of these terms, factor out each term and select the prime factor with the least exponent. Finally, evaluate the product of all prime factors. For instance:12 = 3 x 2²= 2² x 30 x 11044 = 11 x 2²= 2² x 30 x 112² has the least exponent for prime factor 2 of all these factorizations.30 has the least exponent for prime factor 3.110 has the least exponent for prime factor 11.The rest of other "invisible" prime factors, like 5 and 7, have the least exponent, which is 0!Therefore, the gcd is 2² = 4!
Suppose you have a prime factor with an exponent of n. Then that prime factor can appear 0, 1, 2, ... , n times in a compound factor: that is, there are (n+1) different exponents that it can take.
There are no exponents needed. The prime factorization of 102 is: 2 x 3 x 17