No.
[ONLY WORKS FOR REGULAR PENTAGONS] I don't the exact formula, BUT, from what I learned in Geometry last year, I remember that if you have the radius from the center perpendicular to a side [for height] and if you have the length of the side of the pentagon, you can use a simple 1/2 times base time height to get 1/5th of the area. Then you just take that and multiply it by 5 to get the area of the whole pentagon. I know it looks complicated, but it's pretty simple: I have a REGULAR pentagon that I chop into 5 triangles I have the height = 2 I have the base [or the length of 1 side of the pentagon]= 4 1/2xbasexheight= 1/2x2x4= 4 So now you have the area of 1 triangle and multiply by 5 4x5= 20 your pentagon is 20 units squared. I hope this helped.
it is 2 squared
The formula for finding the area of a regular pentagon is: A= 1/4*{sqrt[5(5+2sqrt(5)]}*a^2 where * means multiply, ^2 means 't the power of 2 or squared) You only need the length of the side. So the area of this pentagon is given by A= 1/4{sqrt[5(5+2sqrt(5)]}*.9^2 =1/4*(6.8819)*0.81 = 1.3936 sq mm.
5 x 5 = 25
a squared + b squared = c squared
I use the formula "5 times S squared divided by 4 tan36", where S is the length of the sides, 6 in this instance. 4 tan36 is very close to 2.906 so you have (5 x 6 x 6)/2.906 ie 180/2.906 = 61.941 sqcm
Side length squared is the formula for finding the area of a square.
The area is about 61.94 units squared.
x2+y2
a squared + b squared=c squared
x squared + y squared = z squared.
One method is by only knowing the length of each side and the number of sides. This applies to all regular polygons. In the case of your pentagon the number of sides are of course are 5. The general formula for this method is as follows: A = 1/4 x n x l^2 x cot 180/n where A = area 1/4 = constant (=0.25) l^2 = length of side squared (length must be known) cot = cotangent 180/n = 180 degrees divided by number of sides (for pentagon it is 36 degrees)