One method is by only knowing the length of each side and the number of sides.
This applies to all regular polygons.
In the case of your pentagon the number of sides are of course are 5.
The general formula for this method is as follows:
A = 1/4 x n x l^2 x cot 180/n
where
A = area
1/4 = constant (=0.25)
l^2 = length of side squared (length must be known)
cot = cotangent
180/n = 180 degrees divided by number of sides (for pentagon it is 36 degrees)
The area of a regular pentagon with a radius of 7 is 10.1716. If the radius was 5, the area would be 7.26543.
If 6 is the side of a regular pentagon, the area is 61.937
regular pentagon area of 12 000 m2 and an apothem of 40 m regular pentagon area of 12 000 m2 and an apothem of 40 m need to figure it out from area 12000 m2
That depends on the size of the pentagon, and whether it is regular or not. In general, you can divide the pentagon into three triangles, and calculate the area of each triangle separately.
21.4
the exterior of a regular pentagon is? the exterior of a regular pentagon is?
Area = 440.44 sq feet
What is the area of a regular pentagon with side length of 9.4 feet and an apothem length of 6.5 feet
True
A pentagon can be regular, or irregular.
A regular pentagon has five (5) equilateral triangles within it. Find the area of each triangle (1/2bh where b is the base of the triangle or the length of a side of the pentagon, and h is the height of the triangle or the apothem of the pentagon) and multiply the area of the triangle times five (5).
45 cm