Sqroot x > x if x<1.
Paris is not a numerical value of algebraic expression and so does not have a square root.
Yes, there are several. using the square root sign is the most common, but for some purposes using the power of half - i.e. x0.5 - is easier to think about.
38 is greater than the square root of 38
3 is greater than the square root of 8.
8 is greater than the square root of 60
You can't, because it isn't. The square root of 2 is irrational, but that doesn't make it transcendental. The square root of any positive integer is ALGEBRAIC - and transcendental means "not algebraic".In this case, the square root of 2 is a root of the polynomial equation x squared - 2 = 0; therefore it is algebraic.
It is greater than the negative square root of 8, but smaller than the positive square root of 8.
The square root of 6 is an irrational number. It is also an algebraic number, a quadratic surd, an algebraic integer, a constructible number, and a computable number.
It is greater because the square root of 65 is 8.06.
Five and one fourth is greater than the square root of 26.
No there is not. If you are looking for prime factors of a number and you get to the square root of that number you can stop. Yes, there is. If an integer is not itself a prime, then one of its factors will be less or equal to its square root and the "co-factor" will be greater than or equal to the square root. But both cannot be greater than the square root so, when searching for factors, you can stop when you reach the square root.
The square root of 81 is 9