You can't, because it isn't. The square root of 2 is irrational, but that doesn't make it transcendental. The square root of any positive integer is ALGEBRAIC - and transcendental means "not algebraic".In this case, the square root of 2 is a root of the polynomial equation x squared - 2 = 0; therefore it is algebraic.
It means that it is not algebraic... that is, it is not the root of a polynomial expression with rational coefficients.There are infinitely more transcendental numbers than algebraic numbers, but only a few are of any practical importance... most prominently pi and e, the base of the natural logarithms.All (real) transcendental numbers are irrational, but not all irrational numbers are transcendental. For example, the square root of two is irrational, but it is not transcendental as it is a root of the equation x2 - 2 = 0, a polynomial expression with rational coefficients.
Absolutely not. Transcendental numbers are such values as e, pi, and root 2
The square root of two times the square root of two equals two
The square root of six divided by the square root of two equals the square root of three.
yes * * * * * No it does not. A transcendental number is not rational. It is irrational but, further than that, it is not the root of any polynomial equation with rational coefficients.
5 times the square root of two over 3 times the square root of two equals 5/3
Square root 64 and square root 81
The square root of 36 and the square root of 49.
yes. But I'm too lazy to show you how to prove it.
The square root of two is approximately 1.41
If this is supposed to be a riddle, it's not a very good one. The square root of the number whose square root is two is, obviously, two.
The square root of four twenty-fifths, is two fifths, because of the fact that the square root of four is two and the square root of twenty-five is five.