Only if the domain (the numbers that you put into the function) are "bigger than or equal to zero". If the domain is "all real numbers",(i.e. including negatives) then it is not a one-to-one function. The question will tell you what the domain of the function (i.e. the values of 'x' that you are meant to input).
which of the following is a factor of x2 - 5x - 6
(3x4 + 2x3 - x2 - x - 6)/(x2 + 1)= 3x2 + 2x - 4 + (-3x - 2)/(x2 + 1)= 3x2 + 2x - 4 - (3x + 2)/(x2 + 1)where the quotient is 3x2 + 2x - 4 and the remainder is -(3x + 2).
6
(x + 7)(x - 6)
x2 + X -6 =0 so X2 + X = 6 so X2 = 6-x so X = square root of (6-x) That's as far as I can get it.
x2 - 9x + 18 = (x - 3)(x - 6)
2(x + 2)(x - 2)(x2 + 2x + 4)(x2 - 2x + 4)
This is not factorable. You would have to do the quadratic formula for this problem.
(x - 3)(x^2 + 6)
Yes, both brackets will contain a minus sign. (x -2)(x-6)
x >2 x2 - x - 6/(x2 - 4) (x + 2)(x - 3)/(x + 2)(x - 2) cross out x + 2 (x - 3)/(x - 2) this is the most simplified this can be
This question does not make sense. If it should be X2 x 15X -54, the answer is: X2 -15X + 54 = (X - 6)(X -9)