x2 + 15x + 54 = (x + 6)(x + 9) or (x + 9)(x + 6) since 6*9 = 54 and 6 + 9 = 15However, commutativity is implicit in deriving this factorisation so that the two factorisations are the same.or factor by groupingx2 + 15x + 54= x2 + 6x + 9x + 54= (x2 + 6x) + (9x + 54)= x(x + 6) + 9(x + 6)= (x + 6)(x + 9)
The GCF is 15x.
3x
5x
x2 - 2x - 14 doesn't factor neatly. Applying the quadratic formula, we find two real solutions: 1 plus or minus the square root of 15x = 4.872983346207417x = -2.872983346207417
x2 + 15x + 54 = (x + 6)(x + 9) or (x + 9)(x + 6) since 6*9 = 54 and 6 + 9 = 15However, commutativity is implicit in deriving this factorisation so that the two factorisations are the same.or factor by groupingx2 + 15x + 54= x2 + 6x + 9x + 54= (x2 + 6x) + (9x + 54)= x(x + 6) + 9(x + 6)= (x + 6)(x + 9)
The correct classification of x2 15x is a monomial.
x2-15x+54 factor pairs of 54: 1,54 2,27 3,18 6,9 -1,-54 -2,-27 -3,-18 -6,-9 <-6 and -9 sum to -15 x2-6x - 9x+54 x(x-6) - 9(x-6) (x-6)(x-9)
(x-6)(x-9) I did that by factoring 54 until I found two numbers that added up to 15.
x2+15x+14 = (x+1)(x+14)
(x - 6)(x - 9)
You can't factor it
It's an equation. If you want to solve it for x, you can do so as follows: x2 + 15x = 30 x2 + 15x + (15/2)2 = 30 + (15/2)2 (x + 15/2)2 = 30 + 225/2 x + 15/2 = ± √(285/2) x = (-15 ± √570) / 2
(x + 7)(x + 8)
3x2 + 15x + 6 = 3*(x2 + 5x + 2). There are no further rational factors.
3x2 - 15x + 42 = 3*(x2 - 5x + 14) which cannot be factorised further.
(x-11)(x-4)