Just like numbers, polynomials can be prime in some way, although this is usually referred to as being irreducible. Your polynomial is not in fact irreducible since it can be decomposed into (x-4)(x+3). This also means that plugging in any integer value for x gives a factorisation for the number x^2-x-12, which is (x-4)(x+3), so the value of x^2-x-12 for any integer x can only be prime if either x-4 = 1,-1 or x+3 = 1,-1 so for x=5,3,-2,-4. Now for x=5 we get 25-5-12=8, which is not prime. For x=3 we get 9-3-12=-6, which is not prime either. For x=-2 we have 4+2-12=6, which again is not prime. And for x=-4 we have 16+4-12=8 again, which of course is still not prime. So not only is your polynomial reducible, also any value it takes when plugging in an integer x will be composite. An alternative way of establishing this fact would have been to note that this polynomial only takes even values for any integer x and that the value 2 is not in fact attained for any integer x.
Nope! It's (x+ 1) (x-1). :)
x = ? 42 = x squared minus x
Without an "equals" word or sign somewhere, there is nothing to solve.You only have an expression, not an equation.
I believe it is prime as you have written it. change the end to + 81 and it factors as (2x - 1)(x-9)(x+9)
By factoring I get x-3 divided by x+3
-22 - -22
well, i believe it goes like this (not certain) 25 is the only not prime number so... 3xcubed x squared -5 squared
x2 - 12x + 36 = (x - 6)2
y2-12=5x is an equation. When graphed, it is a parabola.
If you are looking for the zeros of this function: x = -2 plus or minus 2 X the square root of 5.
xsquared minus x minus 72
(x−6)(x+5)