y=3 y^3(y^3-y)= 3^3(3^3-3)= 27(27-3)= 27(24)=648
6y-y3 = 3
If one of them and the other One is exactly the same(capital,letters) then it is equal:D
30
Neither y3x-3 nor 3x-y3 are equations, and so neither of them can have a solution. Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "equals" etc. And using ^ to indicate powers (eg x-squared = x^2).
y3 x y3 - y (3)3 x 3(3) - 3 9 x 9 - 3 = ? 9 x 9= 81 81 - 3 = 78 I hope that solves your problem
y=3 y^3(y^3-y)= 3^3(3^3-3)= 27(27-3)= 27(24)=648
6y-y3 = 3
1
y^3
If one of them and the other One is exactly the same(capital,letters) then it is equal:D
30
Assuming that your question is x - y^3 Then you would do the following: x = -10 y = -3 -10 - (-3)^3 -10 - (-27) -10 + 27 = 17
The GCF of y3, y7, y8 is y3
Neither y3x-3 nor 3x-y3 are equations, and so neither of them can have a solution. Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "equals" etc. And using ^ to indicate powers (eg x-squared = x^2).
x^2/y^3 = x^2*y^(-3)
OK< SO< there are many problems that make the answer 38. A few examples:p-36= 74 where "p" equals 38.x+(-19) = 19 where "x" equals 38.i + 5783 = 5821 where "i" equals 38.94 - 56 - x where "x" equals 38.h +3 = 41 where "h" is equal to 38.y3 +19 = 54891 where "y3" equals 54872 where plain "y" would equal 38 (38x38x38 = 54872).And you could come up with a tON more, but that is some possible ones.