The easiest way is to use a prime sieve (Google Sieve of Eratosthenes).
Here is pseudo-code for the algorithm.
- create a boolean array of size n
- for every true index 2 through n
- - keep the index as true, mark all multiples of the index as false.
So, for example, if n=10
start with 2, keep 2 true. Mark 4,6,8,10 as false.
next is 3, keep it true. mark 6,9 as false (6 was already false).
next is 4, it is false, skip it.
next is 5, keep it true. mark 10 as false (it was already false).
6 is false, skip it
7 is true, keep it true. the next multiple of 7 is greater than 10
8,9, 10 are all false.
you are done - the values marked true (1,2, 3,5,7) are your primes.
#include
using std::cin;
using std::cout;
using std::endl;
int main()
{
int number = 0;
cout << endl << "Enter a number: ";
cin >> number;
for (int i = 0; i <= number; i++)
{
if (i % 2 == 0 && i != 0)
{
cout << endl << "Even number: " << i;
}
}
cout << endl;
system("PAUSE");
return 0;
}
PRINT 2,3,5,7,11,13,17,19,23,29,31,37
Here is a simple program to generate prime numbers upto a given specific number /*Prime No. from 1 to 50*/ /*By-Himanshu Rathee*/ #include<stdio.h> #include<conio.h> void main() { int i,j,n; clrscr(); printf(" Enter the number upto which we have to find the prime number: "); scanf("%d",&n); printf("\n"); for(i=2;i<=n;i++) { for(j=2;j<=i-1;j++) if(i%j==0) break; /*Number is divisble by some other number. So break out*/ if(i==j) printf("\t%d",i); /*Number was divisible by itself (that is, i was same as j)*/ } /*Continue loop upto nth number*/ getch(); }
I am providing a succinct and easy to understand version of the program. I have run it in 3-4 compilers and it works perfect. Mind you, you should not enter a number more than 2147483647 (which is the largest number a variable can process in C!). If you do, no problem, but it will display all numbers above it, including the even numbers to be prime. So here you are:#include#includemain(){long int a,b,c;printf("Enter the number: ");scanf("%ld",&a);for (b=2;b
#include#includebool is_prime(unsigned num) {unsigned max, factor;if (num
Loop through some numbers - for example, 2 through 100 - and check each one whether it is a prime number (write a second loop to test whether it is divisible by any number between 2 and the number minus 1). If, in this second loop, you find a factor that is greater than 1 and less than the number, it is not a prime, and you can print it out.
VBnet program to find the prime numbers between 100 to 200?
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program to find prime number in 8085 microprocessor
29 is a Prime number. There are no prime numbers between 29 and
NO. There are more prime numbers between 1 and 100 than the prime numbers between 101 and 200.number of prime numbers between 1 and 100 = 25number of prime numbers between 101 and 200 = 20
There are no prime numbers between 114 and 126.
There are no prime numbers between 33 and 36.
Prime numbers are numbers that are only divisible by themselves and the number 1. You can write a program to print all prime numbers from 1 to 100 in FoxPro.
The prime numbers between 30 and 40 are 31 and 37.The prime numbers between 30 and 40 are 31 and 37.
The prime numbers between 31 and 50 are 37,41,43,47.
The prime numbers between 12 and 48 are 13,17,19,23,29,31,37,41,43,47.
The prime numbers between 41 and 54 are 43,47,53.