The prime factors of 8,085 are: 3, 5, 7 and 11. 3 x 5 x 7 x 11 = 1,155
The accumulator is a general register that holds a value. It is also a special register that can be used as the target for the result of various arithmetic or logical computations. For instance, if you wanted to add two numbers, you could load the first into the accumulator, add the second to the accumulator, and then store the accumulator where wanted. The instruction register is an internal register that holds the value of the instruction opcode in order for the 8085 to decode and process the instruction. While it is shown on the Intel block diagram for the 8085, it is not directly accessible by the running program - it is for internal use only by the 8085.
jump,b
Mvi a, 04h 3e mvi b, 04 h 04 add b 06 sta 2050 04 hlt 80 32 50 20 76
every odd no. has "1" in its last bit and every even no has "0" (in binary) eg- 2=0010 ,3=0011 4=0100 ,5=0101....and so on so just logically "AND" the no with "01H" using instruction [HAVING THAT NO. IN ACCUMULATOR (A)] ANI 01H so if the no. is even => A=0 (and zero flag is set i.e. "1" but if the no is odd then => A=1 means zero flag is reset i.e. "0" so using instruction "JZ" you can find if the no. if even or odd. :)
A program which is used to count the number of numbers in an array using a 8085 microprocessor is known as a assembly language program.
8085 is a microprocessor designed by Intel
The '8085' in the 8085 microprocessor is the designation given to the microprocessor by Intel. The '5' means it is a single power supply (5 volt) version of the 8080, with enhancements.
+5v necessary for microprocessor 8085.
8085 is a 8 bit microprocessor designed by Intel Co.
with neat diagram explain the system bus structure of 8085
write it in 8085
crystal is a oscilltor in microprocessor
The 8085 is not pipelined.
+5v supply is alone needed for Intel 8085 Microprocessor
HL is a register pair used to store 16 bit of data in 8085 microprocessor.
There are 74 instructions in the 8085 microprocessor.