y=4x+1
Yes, I just made it in the y=mx-b form.
Points: (0, 0) and (4, 1) Slope: 1/4
Points: (0, 0) and (4, 1) Slope: 1/4
Points: (0, 6) and (6,0) and the slope of the line works out as -1
Slope, m, equals (y2-y1)/(x2-x1). Slope is (0-(-1))/(0-(-1)) or 1/1 or 1.
Points: (1, 5) and (0, 2) Slope: 3
To find the slope of the line that goes through the points (0, 0) and (5, 1), use the formula for slope ( m = \frac{y_2 - y_1}{x_2 - x_1} ). Here, ( (x_1, y_1) = (0, 0) ) and ( (x_2, y_2) = (5, 1) ). Plugging in the values, we get ( m = \frac{1 - 0}{5 - 0} = \frac{1}{5} ). Thus, the slope of the line is ( \frac{1}{5} ).
If you mean points of (-10, 1) and (0, -4) then the slope works out as -1/2
The slope is 1/2.
Slope of line: 3 Perpendicular slope: -1/3 Equation: y-2 = -1/3(x-0) => y = -1/3x+2
Points: (1, 5) and (0.2)Slope: 3
If you mean points of: (0, 5) and (10, 0) then the slope is -1/2
The slope is -2/6 = -1/3.