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Slope, m, equals (y2-y1)/(x2-x1). Slope is (0-(-1))/(0-(-1)) or 1/1 or 1.

Q: Find the slope of the line that passes through these points -1 -1 and 0 0?

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No

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Not always. For example, try to find the slope of the line that passes through the points (3, 4) and (2, 3).

Answer: When there is no slope stated in the function of x, when y=mx+b It simply means y=0x+b Since "b" is the y intercept, your line would be a horizontal line parallel to the X-axis passing through point (0,b) Answer: In other cases, you may need to calculate the slope first, from some other information provided. For example, if you are asked to find the equation that passes through two specified points, you can first find the slope between those two points. Then you can use this slope, and one of the points, with the slope-intercept form of the equation.

Points: (2, 5) and (4, 3) Slope: -1 Equation: y = -x+7 in slope-intercept form --- If you want to write the slope-intercept form of the equation of the line passing through the given points, then use the two points to find the slope of the line. After that, use the slope and one of the points to find the y-intercept. For instance, m = (5 - 3)/(2 - 4) = 2/-2 = -1(the slope) y = mx + b (replace m with -1, and (x, y) with (4, 3)) 3 = -1(4) + b 3 = -4 + b (add 4 to both sides) 7 = b Thus, y = -x + 7 is the equation of the line passing through (2, 5) and (4, 3).

Related questions

y=mx+b

1

No

2

1

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Not always. For example, try to find the slope of the line that passes through the points (3, 4) and (2, 3).

To find the slope of a line passing through two points, use the formula (y2 - y1) / (x2 - x1). In this case, the two points are (17, 101). Since there is only one given point, it is not possible to find the slope of the line passing through these points.

It is a straight line with no slope with a 'y' intercept of 2

Slope, m, equals (y2-y1)/(x2-x1). Slope is (8-2)/(8-2) or 1.

The slope of a line can be found using the formula: m = (y2 - y1) / (x2 - x1), where (x1, y1) and (x2, y2) are two points on the line. For the line that passes through the points A(-2, -1) and B(3, 5), we have: m = (y2 - y1) / (x2 - x1) = (5 - (-1)) / (3 - (-2)) = 6 / 5 = 1.2 So the slope of the line that passes through the points A(-2, -1) and B(3, 5) is 1.2.

It's not possible because the given points would be a vertical line parallel to the y axis