Best Answer

There is no answer - it is an error: negative numbers do not have logarithms.

The log if a number tells to what power the (positive) base must be raised to get the number. Raising any positive number to any power will never result in a negative number, so it is an error to try and take the log of a negative number.

Study guides

☆☆

Q: Log -3 equals

Write your answer...

Submit

Still have questions?

Continue Learning about Math & Arithmetic

0.4772

log(x) = 3x = 10log(x) = 103 = 1,000

log3 + logx=4 log(3x)=4 3x=10^4 x=10,000/3

[log2 (x - 3)](log2 5) = 2log2 10 log2 (x - 3) = 2log2 10/log2 5 log2 (x - 3) = 2(log 10/log 2)/(log5/log 2) log2 (x - 3) = 2(log 10/log 5) log2 (x - 3) = 2(1/log 5) log2 (x - 3) = 2/log 5 x - 3 = 22/log x = 3 + 22/log 5

-Log(1.4x10-3)= 2.85 The Log to be used here is the decimal one, not the neperian one.

Related questions

If the log of x equals -3 then x = 10-3 or 0.001or 1/1000.

0.4772

x = 3*log8 = log(83) = log(512) = 2.7093 (approx)

log(-3,2.3914850069628266…i) = 1.26ie. (-3)1÷1.26=2.3914850069628266…i

3^(-2x + 2) = 81? log(3^(-2x + 2)) = log(81) (-2x+2)log(3) = log(81) -2x = log(81)/log(3) - 2 x = (-1/2)(log(81)/log(3)) + 1

log(x) = 3x = 10log(x) = 103 = 1,000

3x = 18Take the logarithm of each side:x log(3) = log(18)Divide each side by log(3):x = log(18) / log(3) = 1.25527 / 0.47712x = 2.63093 (rounded)

log 3 is a constant, so d/dx log3, like d/dx of any constant, equals zero.

log3 + logx=4 log(3x)=4 3x=10^4 x=10,000/3

[log2 (x - 3)](log2 5) = 2log2 10 log2 (x - 3) = 2log2 10/log2 5 log2 (x - 3) = 2(log 10/log 2)/(log5/log 2) log2 (x - 3) = 2(log 10/log 5) log2 (x - 3) = 2(1/log 5) log2 (x - 3) = 2/log 5 x - 3 = 22/log x = 3 + 22/log 5

-Log(1.4x10-3)= 2.85 The Log to be used here is the decimal one, not the neperian one.

Use the identity log(ab) = log a + log b to combine the logarithms on the left side into a single term. Then take antilogarithms (just take the log away) on both sides.