[log2 (x - 3)](log2 5) = 2log2 10
log2 (x - 3) = 2log2 10/log2 5
log2 (x - 3) = 2(log 10/log 2)/(log5/log 2)
log2 (x - 3) = 2(log 10/log 5)
log2 (x - 3) = 2(1/log 5)
log2 (x - 3) = 2/log 5
x - 3 = 22/log
x = 3 + 22/log 5
log(x)+log(8)=1 log(8x)=1 8x=e x=e/8 You're welcome. e is the irrational number 2.7....... Often log refers to base 10 and ln refers to base e, so the answer could be x=10/8
ln is the natural logarithm. That is it is defined as log base e. As we all know from school, log base 10 of 10 = 1 just as log base 3 of 3 = 1, so, likewise, log base e of e = 1 and 1.x = x. so we have ln y = x. Relace ln with log base e, and you should get y = ex
The expression (3 \log 10) can be simplified using the properties of logarithms. Since (\log 10) in base 10 equals 1, we have (3 \log 10 = 3 \times 1 = 3). Therefore, (3 \log 10 = 3).
Take logs of both sides - you can use any base, to give the answer: 10^x = 97 → log(10^x) = log(97) → x log(10) = log(97) → x = log(97) ÷ log(10) If you use common logs (logs to base 10) - highly recommended in this case), then: lg(10) = 1 → x = lg(97)
18.057299999999998
y = 10 y = log x (the base of the log is 10, common logarithm) 10 = log x so that, 10^10 = x 10,000,000,000 = x
log(x)+log(8)=1 log(8x)=1 8x=e x=e/8 You're welcome. e is the irrational number 2.7....... Often log refers to base 10 and ln refers to base e, so the answer could be x=10/8
ln is the natural logarithm. That is it is defined as log base e. As we all know from school, log base 10 of 10 = 1 just as log base 3 of 3 = 1, so, likewise, log base e of e = 1 and 1.x = x. so we have ln y = x. Relace ln with log base e, and you should get y = ex
2 log(x) + 3 log(x) = 105 log(x) = 10log(x) = 10/5 = 210log(x) = (10)2x = 100
log 100 base e = log 100 base 10 / log e base 10 log 100 base 10 = 10g 10^2 base 10 = 2 log 10 base 10 = 2 log e base 10 = 0.434294 (calculator) log 100 base e = 2/0.434294 = 4.605175
The expression (3 \log 10) can be simplified using the properties of logarithms. Since (\log 10) in base 10 equals 1, we have (3 \log 10 = 3 \times 1 = 3). Therefore, (3 \log 10 = 3).
X is the log(to the base 2) of 10 = 3.324(rounded)
Take logs of both sides - you can use any base, to give the answer: 10^x = 97 → log(10^x) = log(97) → x log(10) = log(97) → x = log(97) ÷ log(10) If you use common logs (logs to base 10) - highly recommended in this case), then: lg(10) = 1 → x = lg(97)
log(10) 12 = 1.07918 Then the antilog is 12 = 10^(1.07918) You must specify the base to which to logarithm is functioning. Different log bases will give different answers.
When the unknown is in the power you need to use logs (to any base) and the rule: log(a^b) = b × log(a) Thus: 10^x - 4 = 7 → 10^x = 11 → x log 10 = log 11 → x = log 11 ÷ log 10 If you use common logs (to base 10) then: lg 10 = 1 → x = lg 11 ≈ 1.04
18.057299999999998
The log of infinity, to any base, is infinity.