There is no answer - it is an error: negative numbers do not have logarithms.
The log if a number tells to what power the (positive) base must be raised to get the number. Raising any positive number to any power will never result in a negative number, so it is an error to try and take the log of a negative number.
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0.4772
The expression (3 \log 10) can be simplified using the properties of logarithms. Since (\log 10) in base 10 equals 1, we have (3 \log 10 = 3 \times 1 = 3). Therefore, (3 \log 10 = 3).
log(x) = 3x = 10log(x) = 103 = 1,000
log3 + logx=4 log(3x)=4 3x=10^4 x=10,000/3
[log2 (x - 3)](log2 5) = 2log2 10 log2 (x - 3) = 2log2 10/log2 5 log2 (x - 3) = 2(log 10/log 2)/(log5/log 2) log2 (x - 3) = 2(log 10/log 5) log2 (x - 3) = 2(1/log 5) log2 (x - 3) = 2/log 5 x - 3 = 22/log x = 3 + 22/log 5