log10(225)2 equals 5.5327625985087111
2n=225 Log 2n=Log 225 (taking logarithm on both sides) n Log 2=Log 225 n=Log 225 / Log 2 n=2.35 / 0.301 n=7.81 (answer rounded to 3 significant figure)
5x 12x = 17xx log(5) + x log(12) = x log(17)x [ log(5) + log(12) ] = x log(17)x log(60) = x log(17)x = 0This actually checks. Since anything to the zero power is ' 1 ',50 120 = 1 times 1, or 1and 170 = 1
(12)2x = 28(2x) log(12) = log(28)2x = log(28) / log(12) = 1.34098 (rounded)x = 0.67049 (rounded)
log y (3445.51/2400) / log 1.075 = x
2ⁿ = 20000 → log(2ⁿ) = log(20000) → n log(2) = log(20000) → n = log(20000)/log(2) You can use logs to any base you like as long as you use the same base for each log → n ≈ 14.29
2n=225 Log 2n=Log 225 (taking logarithm on both sides) n Log 2=Log 225 n=Log 225 / Log 2 n=2.35 / 0.301 n=7.81 (answer rounded to 3 significant figure)
7x = 5x log(7) = log(5)x = log(5) / (log(7) = 0.82709 (rounded)
10x = 4.6 therefore log 10x = log 4.6 and that gives x = log 4.6
5x 12x = 17xx log(5) + x log(12) = x log(17)x [ log(5) + log(12) ] = x log(17)x log(60) = x log(17)x = 0This actually checks. Since anything to the zero power is ' 1 ',50 120 = 1 times 1, or 1and 170 = 1
"Log" is not a normal variable, it stands for the logarithm function.log (a.b)=log a+log blog(a/b)=log a-log blog (a)^n= n log a
(12)2x = 28(2x) log(12) = log(28)2x = log(28) / log(12) = 1.34098 (rounded)x = 0.67049 (rounded)
log y (3445.51/2400) / log 1.075 = x
The anti-log of what ??? If log(12) = 1.07918, then antilog(1.07918) = 12 Did you want the anti-log of 12 ? That's 1,000,000,000,000.
3x = 18Take the logarithm of each side:x log(3) = log(18)Divide each side by log(3):x = log(18) / log(3) = 1.25527 / 0.47712x = 2.63093 (rounded)
3^(-2x + 2) = 81? log(3^(-2x + 2)) = log(81) (-2x+2)log(3) = log(81) -2x = log(81)/log(3) - 2 x = (-1/2)(log(81)/log(3)) + 1
250x = 400000 then x log 250 = log 400000 so x = log 400000 / log 250 Natural logs could have been used instead of logs to base 10.
2ⁿ = 20000 → log(2ⁿ) = log(20000) → n log(2) = log(20000) → n = log(20000)/log(2) You can use logs to any base you like as long as you use the same base for each log → n ≈ 14.29