x + y + z = 0 x = a - b, y = b - c, z = c - a, therefore a - b + b - c + c - a = ? a - a + b - b + c - c = 0
y = mx + b
Suppose you want to divide x by y Find log(x) and log(y) to any base b (usually 10 or e) Calculate z = log(x) - log(y) Look up the antilog of z (or find the number whose log is z). x/y = antilog(z)
let's look at log base 2 (x)=8, that means 2^x=8 so x=3 in general if b^y=x, then log base b (x)=y if the base is 1, then we have 1^y=x, but 1^y=1 for all y so it does not work..
y-b/x=m
b y = xlog(b) + log(y) = log(x)
y = 10 y = log x (the base of the log is 10, common logarithm) 10 = log x so that, 10^10 = x 10,000,000,000 = x
Here are a few, note x>0 and y>0 and a&b not = 1 * log (xy) = log(x) + log(y) * log(x/y) = log(x) - log(y) * loga(x) = logb(x)*loga(b) * logb(bn) = n * log(xa) = a*log(x) * logb(b) = 1 * logb(1) = 0
y=logx becomes 10^y=x
You have, y = 6 + log x anti log of it, 10y = (106) x
If: y = x+b then y-x = b
Symmetry, which states that if A = B then B = A Put A = 4 and B = x + y
x + y + z = 0 x = a - b, y = b - c, z = c - a, therefore a - b + b - c + c - a = ? a - a + b - b + c - c = 0
Let b and y be positive numbers, b can't be 1. log base b y = x if and only if b^x=y
x = (y-b)/m
y=logx y=10 logx= 10 10logx = 10log1 logx = log1 x = 1 //NajN
y=m(x)+b