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She has 11 nickels.
In order to eliminate the decimal point, let us work with cents. So, let $ 4.50 = 450 cents. If the number of nickels is x, then the value of x nickels is 5x cents. Since the number of dimes is twice the number of nickels, then we can write the number of dimes as 2x, and the value of 2x dimes as 10(2x) or 20x cents. So we have: 5x + 20x = 450 25x = 450 divide by 25 to both sides x = 18 the number of nickels 2x = 2 x 18 2x = 36 the number of dimes Thus, Cameron has 18 nickels and 36 dimes. Check: 18 nickels = 18 x 5 cents = 90 cents or $ 0.90 36 dimes = 36 x 10 cents = 360 cents or $ 3.60 0.90 + 3.60 = 4.50? 4.50 = 4.50 True
If there are 150 nickles and dimes and 70 more are nickles than dimes how many of each are there?
Nickles - 10 $0.50dimes - 20 $2.00quarters - 40 $10.000.50+2.00+10.00 = $12.50 containing 40 quarters---Here's how to solve this with Algebra :Let N be the number of nickels, so that2N is the number of dimes, and2(2N) or 4N is the number of quarters.A nickel is 5 cents, a dime is 10 cents, and a quarter is 25 cents,and the total in the cash register is $12.50Multiplying by their cents values, we have5(N) plus 10(2N) plus 25 (4N) = 12505N + 20N + 100N = 1250125 N = 1250N= 10So the number of nickels is 10, dimes 20, and quarters 40.
Ten dimes, fifteen nickels
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You do. 6 dimes = 60 cents 9 nickels = 45 cents 6 dimes = 12 nickels
5 dimes = 50 cents 3 nickels = 15 cents Total is 65 cents
Nickels are worth five cents and dimes are worth ten.
6 dimes, 5 dimes 2 nickels, 4 dimes 4 nickels, 3 dimes 6 nickels, 2 dimes 8 nickels, 1 dime, 10 nickels, and 12 nickels.
2 dimes and 5 nickels
5 nickels and three dimes
3 dimes is 30 cents and 5 nickels is 25 cents so 3 dimes is worth more.
1 quarter, 4 dimes , 2 nickels
11 dimes.
14 nickels = 70 cents 3 dimes = 30 cents 14 nickels + 3 dimes = 1.00
43 dimes and 30 nickels