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Q: Molar mass is a whole number multiple of the a) empirical formula mass c) average atomic mass b) amu d) mass percent?
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Calculate the empirical formula of a compound formed from 3 percent C 0.3 percent H and 96.7 percent you Which formula below correctly represents the empirical formula?

Chi a+


Calculate the empirical formula of a compound formed from 3 percent c 3 percent h and 96 7 percent you which formula below correctly represents the empirical formula?

CHI3


What is the empirical formula for vanillin with 63.15 percent 5.30 percent 31.55 percent percent composition?

C3 h3o


How do you calculate the molecular formula of a substance which contain 80 percent C and 20 percent H?

You can only calculate the empirical formula because you do not have a mass of this compound given. To do the empirical formula assume 100 grams and change percent to grams. Get moles. 80 grams Carbon (1 mole C/12.01 grams) = 6.66 moles C 20 grams hydrogen (1 mole H/1.008 grams) = 19.84 moles H the smallest becomes 1 in the empirical formula and the other number is divided by it, Thus; H/C 19.84 moles H/6.66 moles C = 2.9, which we call 3 so, CH3 --------------- is the empirical formula To get the molecular formula tour question needed to read; How to calculate molecular formula from such ans such mass of compound with these percentages of elements, Which, of course, your question did not provide. Then you would have divided that given mass by the mass total of the elements of the empirical formula, got a whole number by which you would have multiplied the numbers of your empirical formula to get molecular formula.


What is the empirical formula for 5.17 percent 35.9 percent and 58.9 percent?

to get 5.17% of a number, multiply it by 0.0517 to get 35.9% of a number, multiply it by 0.359, and to get 58.9% of a number, multiply it by 0.589

Related questions

Can you determine the molecular formula of a substance from its percent composition?

Not completely. The empirical formula of a substance can be determined from its percent composition, but a determination of molecular weight is needed to decide which multiple of the empirical formula represents the molecular formula.


Calculate the empirical formula of a compound formed from 3 percent C 0.3 percent H and 96.7 percent you Which formula below correctly represents the empirical formula?

Chi a+


Calculate the empirical formula of a compound formed from 3 percent c 3 percent h and 96 7 percent you which formula below correctly represents the empirical formula?

CHI3


What is the empirical formula for a compound that is 43.6 percent and 56.4 percent oxygen?

P2o5


What is the empirical formula of 7.8 percent carbon and 92.2 percent chlorine?

CCl4


What is the empirical formula for a molecule containing 46.8 percent si and 53.2 percent o?

The empirical formula for a molecule containing 46.8 percent si and 53.2 percent o is in the middle of the two. These added together and divided by two will net the average result.


Explain why the percent composition of certain compounds are not sufficient to determine the compounds molecular formulas?

Because unlike the empirical formula, the molecular formula does not have to be the simplest ratio.If by chance you are given the percent composition of the elements in a substance, you could calculate the empirical formula and then the empirical formula's mass. However, the molecular formula equation is molecular formula= (empirical formula)n, where n is the mass of the molecular formula divided by the mass of the empirical formula. You would, therefore, need to know the mass belonging to the molecular formula, which you are not given.


If a compound containing chromium and silicon has 73.52 mass percent chromium what is its empirical formula?

Cr3Si2 is the empirical formula for a compound containing chromium and silicon an has 73.52 mass percent chromium.


What is the empirical formula for a compound that is 43.6 percent phosphorus and 56.4 percent oxygen?

p2o5


75.7 percent arsenic and 24.3 percent oxygen what empirical formula would it have?

As2O3


What would the empirical formula be for 66 percent Barium and 34 percent Chlorine?

BaCl2


What is the empirical formula for 13 percent magnesium and 87 percent bromine?

mg br3