BaCl2
The empirical formula for a substance containing 65.95% barium and 34.05% chlorine would be BaCl2 (barium chloride). This is determined by converting the mass percentage of each element to moles, finding the ratio of moles of each element, and simplifying to the simplest whole-number ratio.
Formula: Ba3N2
The empirical formula for barium sulfide (BaS) is one barium atom bonded to one sulfur atom.
barium chloride
The compound formed between barium and chlorine would be barium chloride (BaCl2). In this compound, barium has a +2 charge and chlorine has a -1 charge, so two chlorine atoms are needed to balance the charge of one barium atom.
The elements in Barium Chloride (BaCl2) are Barium (Ba) and Chlorine (Cl).
The name is Barium Chloride because it is the reaction of Barium (Ba2+) with Chlorine (Cl-).
Barium chloride consists of one barium atom and two chlorine atoms in each molecule, so there are a total of three atoms in one molecule of barium chloride.
The ionic compound formed from Barium (Ba) and Chlorine (Cl) is Barium Chloride, with a chemical formula BaCl2.
BaClO32 is not a valid chemical formula. It appears to be a combination of the elements barium (Ba), chlorine (Cl), and oxygen (O). The correct formula for barium chlorate is Ba(ClO3)2.
The reaction between chlorine and barium is called a single displacement reaction, where the chlorine displaces the barium in barium chloride to form barium chloride and elemental chlorine. The balanced equation for this reaction is: Cl2 + Ba → BaCl2 + Cl2
The formula of the hydrate is BaCl2•2H2O. The ratio of barium chloride to water is 1:2, so there are two moles of water for every mole of barium chloride in the compound.