Ms. Washington can put 5 students into 7 rows or put 7 people into 5 rows.
No.
The number of ways to arrange six students in a lunch line can be calculated using the factorial of the number of students. Specifically, this is 6! (6 factorial), which equals 6 × 5 × 4 × 3 × 2 × 1 = 720. Therefore, there are 720 different ways to arrange six students in a lunch line.
To determine how many ways a teacher can arrange 5 students in the front row from a total of 23 students, we use permutations since the order matters. The number of ways to choose and arrange 5 students from 23 is given by the formula ( P(n, k) = \frac{n!}{(n-k)!} ), where ( n ) is the total number of students and ( k ) is the number of students to arrange. Thus, it is calculated as ( P(23, 5) = \frac{23!}{(23-5)!} = \frac{23!}{18!} = 23 \times 22 \times 21 \times 20 \times 19 = 2,598,960 ). Therefore, there are 2,598,960 different ways to arrange 5 students in the front row.
how do you arrange these number 22.8, 8.2,8.02,28.2,2.8
You can arrange them in one row or column of 11 tiles, identifying the number as prime.
The number of students is discrete. There is no number of students between 4 and 5.
by number of protons
arrange the set of number in order from least to greatest and the middle number is the median. You have to arrange them in order from least to greatest or it's wrong. (or greatest to least)
There were 7 (Seven) delegates in his first cabinet.
That depends on if the variable "number of students" is dependent on something else. For example, if the number of students is dependent on the time of year, then it is charted along the y-axis. If the number of students is independent, and the school's yearly expenses are dependent on the number of students, than the number of students should be tracked by the x-axis.
need to arrange 5/8,1/2,4/11 in increasing order
Three