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Ms. Washington can put 5 students into 7 rows or put 7 people into 5 rows.

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15y ago

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The number of ways to arrange six students in a lunch line can be calculated using the factorial of the number of students. Specifically, this is 6! (6 factorial), which equals 6 × 5 × 4 × 3 × 2 × 1 = 720. Therefore, there are 720 different ways to arrange six students in a lunch line.


How many ways can a teacher arrange 5 students in the front row of a classroom with a total of 23 students?

To determine how many ways a teacher can arrange 5 students in the front row from a total of 23 students, we use permutations since the order matters. The number of ways to choose and arrange 5 students from 23 is given by the formula ( P(n, k) = \frac{n!}{(n-k)!} ), where ( n ) is the total number of students and ( k ) is the number of students to arrange. Thus, it is calculated as ( P(23, 5) = \frac{23!}{(23-5)!} = \frac{23!}{18!} = 23 \times 22 \times 21 \times 20 \times 19 = 2,598,960 ). Therefore, there are 2,598,960 different ways to arrange 5 students in the front row.


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