The question is vague, but if you are talking about a square, then the perimeter is 28.
The perimeter is 56.
If the width is seven on both sides and the length is seven on both sides then the perimeter is 7+7+7+7 = 28.
The perimeter of a rhombus is calculated by adding the lengths of all four sides. Since all sides of a rhombus are equal, the formula for the perimeter is ( P = 4s ), where ( s ) is the length of one side. Given that the perimeter is 28 inches, you can find the length of one side by dividing the perimeter by 4: ( s = 28 \div 4 = 7 ) inches. Therefore, the length of one side of the rhombus is 7 inches.
P =100
The perimeter of a regular hexagon is (6 x the length of one side).
With a rectangle, opposite sides will be the same length. So you have 5+5, and 7+7. That adds up to 24, which is the distance around the outside, or perimeter.
the perimeter of a square that has a side length of 7 cm is........28cm squared
sum of length of all 7 sides
Assuming that 7 and 9 are the lengths - in some units - of the sides of a rectangle, its perimeter is 32 units of length.
The perimeter of a heptagon can be calculated by multiplying the length of one side by the total number of sides. Since a heptagon has seven sides, the perimeter would be (7 \times 14 , \text{cm} = 98 , \text{cm}). Therefore, the perimeter of the heptagon is 98 cm.
The perimeter is all the sides added together so it would Be 3+3+7+7 the perimeter is 20
A parallelogram is a "sat-on" rectangle; opposite sides are equal in length → perimeter = 7 + 11 + 7 + 11 inches = 36 inches.