Assuming the object is shape with opposite sides of equal length then the perimeter would measure 2 * 7 + 2 * 2 =18
60 and 62
Perimeter = 2*(L+W) = 2*(3+7) = 2*10 = 20 yards. By the way, conventionally, the length is the bigger dimension.
The perimeter of a rectangle is calculated by adding up all the sides. In this case, the width is x - 7 units and the length is 3x + 10 units. Therefore, the perimeter would be P = 2(width) + 2(length). Substituting the given values, we get P = 2(x - 7) + 2(3x + 10) = 2x - 14 + 6x + 20 = 8x + 6 units.
To find all the rectangles with a perimeter of 26 cm, we can use the formula for the perimeter of a rectangle: P = 2(l + w), where P is the perimeter, l is the length, and w is the width. Since the perimeter is given as 26 cm, we have 26 = 2(l + w). We can then list all the possible combinations of length and width that satisfy this equation, such as (length 10 cm, width 3 cm), (length 8 cm, width 5 cm), and so on.
perimeter = 2(length X width) = 2(l x w) = 2(w+7+w) - 2(2w+7)=142 2w+7 = 71; 2w=64; w = 32 and l = w+7 = 39 Check: perimeter = 2(32+37) = 142
Rectangles Perimeter Is 2L + 2W. 2(7) + 2(4) = Perimeter 14 + 8 = Perimeter Perimeter = 22
Perimeter = 2*(7+9) = 32 units.
Perimeter = 2*(Length + Width) 14 = 2*(L + 2) 7 = L + 2 so L = 5 metres.
Perimeter = length + length + width + width Let "w" = width, then "7w" must equal the length (because it's 7 times the width) 7w + 7w + w + w = perimeter 16w = perimeter
width:10,length;17 17*2+10*2=54
44
length + width = ½ perimeter ie 24', so length = 24 - width length = 2 x width + 3, so 24 - width = 2 x width + 3 ie 21 = 3 x width so width = 7 and length = 17
length 18 width 7
twelve -------------------- The original rectangle is 12 feet in length and 5 feet in width. The length (12) is 7 feet greater than the width (5 feet). Were the length decreased by 3 (12 - 3 = 9) and the width increased by 2 (5 + 2 = 7), the perimeter would be 32 feet (9 + 7 + 9 + 7 = 32).
width=5 length=12
60 and 62
Perimeter = 2*(L+W) = 2*(3+7) = 2*10 = 20 yards. By the way, conventionally, the length is the bigger dimension.