Assuming the object is shape with opposite sides of equal length then the perimeter would measure 2 * 7 + 2 * 2 =18
26 meters The perimeter (distance around the outside) = length + width + length + width P = 2L + 2W 2 (7) + 2 (6) = 26
60 and 62
Perimeter = 2*(L+W) = 2*(3+7) = 2*10 = 20 yards. By the way, conventionally, the length is the bigger dimension.
32 meters The perimeter (distance around the outside) = length + width + length + width P = 2L + 2W 2 (9) + 2 (7) = 18 + 14 = 32 also: P = 2 (L + W) 2(9 + 7) = 32
perimeter = 2(length X width) = 2(l x w) = 2(w+7+w) - 2(2w+7)=142 2w+7 = 71; 2w=64; w = 32 and l = w+7 = 39 Check: perimeter = 2(32+37) = 142
Rectangles Perimeter Is 2L + 2W. 2(7) + 2(4) = Perimeter 14 + 8 = Perimeter Perimeter = 22
Perimeter = 2*(7+9) = 32 units.
Perimeter = 2*(Length + Width) 14 = 2*(L + 2) 7 = L + 2 so L = 5 metres.
Perimeter = length + length + width + width Let "w" = width, then "7w" must equal the length (because it's 7 times the width) 7w + 7w + w + w = perimeter 16w = perimeter
width:10,length;17 17*2+10*2=54
22 meters The perimeter (distance around the outside) = length + width + length + width P = 2L + 2W 2 (4) + 2 (7) = 22
26 meters The perimeter (distance around the outside) = length + width + length + width P = 2L + 2W 2 (7) + 2 (6) = 26
44
length + width = ½ perimeter ie 24', so length = 24 - width length = 2 x width + 3, so 24 - width = 2 x width + 3 ie 21 = 3 x width so width = 7 and length = 17
length 18 width 7
width=5 length=12
60 and 62