y = -2x + 6
slope = m = -2 = -2/1 = rise/run
y-intercept: 6
x-intercept: 3
y = 0
0 = -2x +6
0 + 2x = -2x + 2x + 6
2x = 6
2x/2 = 6/2
x = 3
So we have two points (3, 0) and (0, 6). We can find another point using the slope -2/1.
Use the point (0, 6):
(0 + 1, 6 - 2) = (1, 4)
Draw the line that passes through the points (0, 6), (1, 4), and (3, 0).
That would be a linear equation.
No, y=8 is a fixed value. A linear equation would look something like y=x+8 - That would produce a straight line graph if the values of x & y were plotted against each other on a graph.
Since y=14x is a perfect linear relation, the correlation would be 1.
The question contains an expression, not an equation. An expression does not have a graph. Furthermore, even if it were an equation, its form suggests that it would be a linear equation and a linear equation does not open in any direction.
If you mean y = 2^x, then no, it is not a linear equation. This is an exponential equation. The graph of this exponential equation would start out near zero on the left-hand side (there is a horizontal asymptote at y = 0) and would gradually increase as you move to the right: overall, it has a curved shaped. If you mean y = 2x, then yes, it is a linear equation.
You would draw a straight horizontal line through the 5 on the y axis.
A linear equation describes a line like 2x+1=y. If you were to graph that equation, then it would give you a line. A quadratic equation is like x^2+2x+1=y. Graphing this equation would give you a U shaped graph called a parabola.
Well I cant graph it for you but its a linear line some points would be (0,-1) (1,-2) (2,-3)(3,-4) (-1,0) (-2,1) (-3,2) and so on
The equation 0 equals 0 is an identity and contributes absolutely nothing to the part of the graph that you should shade or not. The tautological statement can be ignored.
No, this is not a function. The graph would have a vertical line at x=-14. Since there are more than one y value for every given x value, the equation does not represent a function. The slope of the equation also does not exist.
Move 3 over the right side of the equation so the equation would be x = -3. The graph of this would be a verticle line at x= -3
To determine the trend of linear function graph or equation you would simply look at the slope of the line. This is represented by the m in the equation, f(x) = mx + b.