18.02775638 feet
multiply the base of the triangle by the height then halve the answer.
Using Pythagoras' Theorum: (height)^2 = (hypotenuse)^2 - (base)^2
The area of a right angled triangle would be .5 * length *width where the length is the height of the triangle. To find the height of the triangle, take the sine of 45 degrees, which is the degree of the angles other than the 90 degrees, and multiply it by the length of one of the two equal sides. The width of the triangle is the length of the bottom side.
The two sides are called base and height and the sloping part of the right angle triangle is called the hypotenuse.
Any value that you like. There is no limit to how small not how large it can be.
1/2*base of triangle*height(the perpendicular)=Area of right angled triangle
An isosceles, possibly equilateral, triangle
multiply the base of the triangle by the height then halve the answer.
Using Pythagoras' Theorum: (height)^2 = (hypotenuse)^2 - (base)^2
area = base * height / 2;
The area of a right angled triangle would be .5 * length *width where the length is the height of the triangle. To find the height of the triangle, take the sine of 45 degrees, which is the degree of the angles other than the 90 degrees, and multiply it by the length of one of the two equal sides. The width of the triangle is the length of the bottom side.
Multiply the area by two then divide by the height - assuming that it is a right angled triangle.
height*height+base*base=hypotnuse*hypotnuse where hypotenuse is the longest side in a right angled triangle
The two sides are called base and height and the sloping part of the right angle triangle is called the hypotenuse.
The area of a triangle is one half base times height. In the case of a right triangle, the base is one leg and the height is the other leg. (The two legs being separated by the right angle.)
Any value that you like. There is no limit to how small not how large it can be.
1/2*12*35 = 210 km2