1/2*base of triangle*height(the perpendicular)=Area of right angled triangle
Pythagoras's' theorem or "got an want" on a right angled triangle but use sine rule on a non right angled triangle !! ..
For all triangles, right-angled included, it is the multiplication of the base length times the perpendicular height x half. Algebraically A = 0.5bh For a right-angled triangle it is the base length times to length of right angled (perpendicular) line times one half.
Pythagoras
It depends on what else you know about the triangle.
It is a right angled triangle with legs of equal length.
how to find the perimeter of a right angled triangle using the area
The area of a 12cm by 5cm right-angled triangle is: 42 cm2
multiply the base of the triangle by the height then halve the answer.
the area of a right angled triangle is 30sqcm one leg is 6cm what is the length of the other one
The area of a right-angled triangle with base 8 cm and hypotenuse 10 cm is: 24 cm2
An acute angled triangle, right angled triangle or obtuse angled triangle.
A right triangle is easy, simply multiply the two sides and divide by two
a scalene can be a right-angled triangle or a obtuse angled triangle or a acute angled triangle depending on the angles of the triangle.
acute angled triangle,right angled triangle,obtuse angled triangle,isosceles triangle,equilateral triangle, scalene triangle
a right angled triangle is special because it is the only triangle that has a right angle with a dregree of 180.
There is no right triangle on the right! (Ignore the length of the hypotenuse of a right triangle.) if you have the length of the two legs (base and the upright side): (base x upright) ÷ 2 = area of the right angle triangle.
area = base * height / 2;