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Q: Perfect square divisible by 8 9 10?

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Unless I've made a mistake, it's 3600 which is 60 * 60.

3600 is the smallest perfect square divisible by 8,9 and 10. Work out the prime factorisations for each of the numbers 8, 9, 10: 8 = 23 9 = 32 10 = 2 x 5 So the perfect square must be a multiple of the lcm of 8, 9 & 10 = 23 x 32 x 5 to be divisible by all three numbers. All perfect squares have even powers for all their primes (in their prime factorisation), so to make all the powers even the smallest multiplier of this is 2 x 5, giving 24 x 32 x 52 = 3600.

3600. None of the other three are divisible by 9 so they don't even get to the starting line.

8 is a perfect cube; it is not a perfect square. Its square root is a fraction and the square root of a perfect square is always an integer....you're thinking of 9...

It is not divisible by 10. The remainder is 8.

No, 8648246286104 is not divisible by 10, but 8648246286104 is divisible by 2 and 8

80 is divisible by 4 and 10 and its digits differ by 8.

then you would have a perfect square

The number 8 is not a perfect square because it is not classified as the product of two positive integers. The number 8 is classified as a perfect cube, however.

4 is the perfect square for the factor 12.

Out of that list, 40 is divisible by 2, 4, 5, 8 and 10.

Yes, 64 is a perfect squarebecause 64 = 8*8

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