3600 is the smallest perfect square divisible by 8,9 and 10.
Work out the prime factorisations for each of the numbers 8, 9, 10:
8 = 23
9 = 32
10 = 2 x 5
So the perfect square must be a multiple of the lcm of 8, 9 & 10 = 23 x 32 x 5 to be divisible by all three numbers.
All perfect squares have even powers for all their primes (in their prime factorisation), so to make all the powers even the smallest multiplier of this is 2 x 5, giving 24 x 32 x 52 = 3600.
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10 has no perfect square factors (other than the trivial factor 1).
-10
You can take out the perfect square 4: root(40) = root(4 x 10) = root(4) x root(10) = 2 root(10).
There are 90 two-digit numbers from 10 to 99. Of those, 6 are perfect squares (16, 25, 36, 49, 64, and 81) and 2 are perfect cubes (27 and 64). Each perfect square or root has a probability of 1 in 90 in being drawn.
If you mean: n2+20n+100 then yes it is because (n+10)(n+10) when factored