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Perimeter of 20 cm area 24 cm what is the length and width in cm?
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How do you find the length of a rectangle if the perimeter is 40 and the width is 2inches?
perimeter = 2 x (length + width) ⇒ length + width = perimeter ÷ 2 ⇒ length = (perimeter ÷ 2) - width So to find the length of the given rectangle, subtract the width from half the perimeter is how to do it. IF you meant "What is the length..." then: length = perimeter ÷ 2 - width = 40 ÷ 2 - 2 in = 20 - 2 in = 18 in
The perimeter of the rectangle is 18 and the area is 20 what is the length?
Its length could be 5 units and its width 4 units.
The perimeter of a rectangle is 18 feet and the area of the rectangle is 20 square feetWhat is the length of the rectangle?
Length: 4; Width: 5 or Length: 5; Width: 4
What is the length of a rectangle if the perimeter is 20 feet and the area is 24 square feet?
The length should be 6cm and the width is 4cm.
The length of a rectangle is 4cm longer than the width if the perimeter of the rectangle is 20cms what is the area of the rectangle?
Let the length be x+4 and the width be x: 2(length+width) = perimeter 2(x+4+x) = 20 2x+8+2x = 20 4x = 20-8 4x = 12 x = 3 Therefore: length = 7 cm and the width = 3 cm Area = length*width = 7*3 = 21 square cm
How do you find the length of a rectangle if the perimeter is 40 and the width is 2inches?
perimeter = 2 x (length + width) ⇒ length + width = perimeter ÷ 2 ⇒ length = (perimeter ÷ 2) - width So to find the length of the given rectangle, subtract the width from half the perimeter is how to do it. IF you meant "What is the length..." then: length = perimeter ÷ 2 - width = 40 ÷ 2 - 2 in = 20 - 2 in = 18 in
The perimeter of the rectangle is 18 and the area is 20 what is the length?
Its length could be 5 units and its width 4 units.
The perimeter of a rectangle is 18 feet and the area of the rectangle is 20 square feetWhat is the length of the rectangle?
Length: 4; Width: 5 or Length: 5; Width: 4
What is the length of a rectangle if the perimeter is 20 feet and the area is 24 square feet?
The length should be 6cm and the width is 4cm.
The length of a rectangle is 4cm longer than the width if the perimeter of the rectangle is 20cms what is the area of the rectangle?
Let the length be x+4 and the width be x: 2(length+width) = perimeter 2(x+4+x) = 20 2x+8+2x = 20 4x = 20-8 4x = 12 x = 3 Therefore: length = 7 cm and the width = 3 cm Area = length*width = 7*3 = 21 square cm
The length of a rectangle is 4cm longer than the width If the perimeter of the rectangle is 20 centimeters what is the area of the rectangle?
The perimeter of a rectangle is 2length +2 width. the width is x the length is x+4. Plug into the equation 2(x)+2 (x+4)=20 2x+2x+8=20 4x=12 x=3 The width is 3 the length is 7 (3+4) Area is length times width. 3(7)= 21. the area is 21 centimeters
If 2 rectangles have the same area must they have the same perimeter?
Not at all.Rectangle A:-- Length = 20-ft, Width = 10-ft.-- Area = 200 square ft-- Perimeter = 60-ftRectangle B:-- Length = 16-ft, Width = 12.5-ft-- Area = 200 square ft-- Perimeter = 57-ftRectangle C:-- Length = 40-ft, Width = 5-ft-- Area = 200 square ft-- Perimeter = 90-ftRectangle D:-- Length = 50-ft, Width = 4-ft-- Area = 200 square ft-- Perimeter = 108-ftRectangle E:-- Length = 100-ft, Width = 2-ft-- Area = 200 square ft-- Perimeter = 204-ftRectangle F:-- Length = 800-ft, Width = 3 inches-- Area = 200 square ft-- Perimeter = 1600-ft 6-in
What would the length be of a rectangle that length was six feet and width was 4 feet?
6 feet... area 24 perimeter 20
What is the length of a rectangle when the perimeter is 60 and the length is twice the width?
The length is 20 units and the width is 10 units
What is the length and width of a rectangle that has a perimeter of 20 inches and an area of 24.4524 square inches showing work with final answers?
What do we know about the perimeter of a rectangle? perimeter = 2 × (length + width) → 2 × (length + width) = 20 in → length + width = 10 in → length = 10 in - width What do we know about the area of a rectangle: area = length × width → length × width = 24.4524 in² But from the perimeter we know the length in terms of the width and can substitute it in: → (10 in - width) × width = 24.4524 in² → 10 in × width - width² = 24.4524 in² → width² - 10 in × width + 24.4524 in² = 0 This is a quadratic which can be solved by using the formula: ax² + bx + c → x = (-b ±√(b² - 4ac)) / (2a) → width = (-10 ±√(10² - 4 × 1 × 24.4524)) / (2 × 1) in → width = -5 ± ½√(100 - 97.8096) in → width = -5 ±½√2.1904 in → width = -5 ± 0.74 in → width = 4.26 in or 5.74 in → length = 10 in - 4.26 in = 5.74 in or 10 in - 5.74 in = 4.26 in (respectively) By convention the width is the shorter length (though it doesn't have to be) making the width 4.26 in and the length 5.74 in. Thus the rectangle is 5.74 in by 4.26 in
What is the perimeter of a rectangle that has a length of 4 and a width of 6?
20
What is the length and width for a square with the perimeter of 80 units?
20 x 20
