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Time period of a seconds pendulum is 99.3955111cm at a place where the gravitational acceleration is 9.8m/s2

Q: Period of seconds pendulum

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5.94 m

2.01 seconds.

The period of a simple pendulum of length 20cm took 120 seconds to complete 40 oscillation is 0.9.

It doesn't matter what unit you use to measure the physical length of the pendulum. As a matter of fact, it doesn't matter what unit you use to measure the duration of its period either. If both are at rest on the same planet, then the penduum with the longer string has the longer period. Period!

The period of a pendulum (in seconds) is 2(pi)√(L/g), where L is the length and g is the acceleration due to gravity. As acceleration due to gravity increases, the period decreases, so the smaller the acceleration due to gravity, the longer the period of the pendulum.

Related questions

This pendulum, which is 2.24m in length, would have a period of 7.36 seconds on the moon.

The period of a 0.85 meter long pendulum is 1.79 seconds.

For a simple pendulum: Period = 6.3437 (rounded) seconds

A pendulum with a period of five seconds has a length of 6.21 meters.

Approx 80.5 centimetres.

The period is 1 second.

5.94 m

2.01 seconds.

The period of a simple pendulum of length 20cm took 120 seconds to complete 40 oscillation is 0.9.

For small amplitudes, the period can be calculated as 2 x pi x square root of (L / g). Convert the length to meters, and use 9.8 for gravity. The answer will be in seconds. About 1.4 seconds.

5 seconds

The equation is: http://hyperphysics.phy-astr.gsu.edu/HBASE/imgmec/pend.gif T is the period in seconds, L is pendulum length in cm, g is acceleration of gravity in m/s2. We know on earth the period is 1s when the acceleration of gravity is 9.8m/s2, so the pendulum length is 24.824cm. The acceleration of gravity on the moon is 1.6m/s2. Substitute 24.824cm for L and 1.6 for g and you yield 2.475 seconds. The period is 2.475 seconds.