For a simple pendulum: Period = 6.3437 (rounded) seconds
If you mean what units, that would be meters.
meters
With a simple pendulum, provided the angular displacement is less than pi/8 radians (22.5 degrees) it will be a straight line, through the origin, with a slope of 2*pi/sqrt(g) where g is the acceleration due to gravity ( = 9.8 mtres/sec^2, approx). For larger angular displacements the approximations used in the derivation of the formula no longer work and the error is over 1%.
Usually, you would use kilometers.
Personally nothing as I would use imperial measures, but meters are used to measure any linear length, eg the length of a table, the width of a table, the distance around a running track, etc.meters can be used to measure smaller things, eg the length of a pencil, but this would be a fraction of a meter and centimeters (hundredths of meters) would be used instead to keep the numbers simple.Similarly, longer distances, like 1500 meters or 10,000 meters (distances run in athletic competitions), could be measured, but to make the numbers simpler, kilometers (1000 meters) would be used.Once astronomical distances are reached, meters or kilometers could be used, but light years are used instead to keep the numbers simpler. A light year is the distance that light travels in 1 year which is approx 9.46 × 1015 meters (another length measured in meters!)
This pendulum has a length of 0.45 meters. On the surface of the moon, its period would be 3.31 seconds where g = 1.62m/s^2
Yes. Given a constant for gravity, the period of the pendulum is a function of it's length to the center of mass. In a higher gravity, the period would be shorter for the same length of pendulum.
It doesn't matter what unit you use to measure the physical length of the pendulum. As a matter of fact, it doesn't matter what unit you use to measure the duration of its period either. If both are at rest on the same planet, then the penduum with the longer string has the longer period. Period!
This pendulum, which is 2.24m in length, would have a period of 7.36 seconds on the moon.
Making the length of the pendulum longer. Also, reducing gravitation (that is, using the pendulum on a low-gravity world would also increase the period).
The PERIOD of a Simple Pendulum is affected by its LENGTH, and NOT by its Mass or the amplitude of its swing. So, in your case, the Period of the Pendulum's swing would remain UNCHANGED!
You mean the length? We can derive an expression for the period of oscillation as T = 2pi ./(l/g) Here l is the length of the pendulum. So as length is increased by 4 times then the period would increase by 2 times.
Yes. The period of the pendulum (the time it takes it swing back and forth once) depends on the length of the pendulum, and also on how strong gravity is. The moon is much smaller and less massive than the earth, and as a result, gravity is considerably weaker. This would make the period of a pendulum longer on the moon than the period of the same pendulum would be on earth.
Since the period of a simple pendulum (for short swings) in proportional to the square root of its length, then making the length one quarter of its original length would make the period one half of its original period.Periodapproximately = 2 pi square root (length/acceleration due to gravity)
It would tend towards infinity
A longer pendulum will result in a longer period. The clock would go slower.
Time period is directly proportional to the square root of the length So as we increase the length four times then period would increase by ./4 times ie 2 times.