Study guides

Q: Product of three consecutive natural number is 120 what is their sum?

Write your answer...

Submit

Related questions

No. Every third consecutive natural number is divisible by 3.

111, 112 and 113.

0,6,18,36,60,90,126,168, etc

There must be three consecutive integers to guarantee that the product will be divisible by 6. For the "Product of three consecutive integers..." see the Related Question below.

Any two consecutive numbers must comprise one odd and one even number, so their product must be even. Any three consecutive numbers must include two consecutive numbers so the result still applies.

No.

The three consecutive numbers whose sum and product are the same are 1, 2, and 3.

-7

9240 is the product of the three consecutive integers 20, 21, and 22.

four

0, 1, 2

270

Not sure what thress is. If three, then there is no answer since the sum (or product) of any three consecutive integers must be divisible by 3.

the product of two consicutive multiple of three integers

As the number 1 is considered a special case and not a prime, there cannot be three consecutive numbers that are prime. Any three consecutive numbers must include at least one even number. With the exception of the number 2, no even numbers are prime.

3,4,5

24,25,26

If you define a rectangular number as a number which is the product of two consecutive integers, none of them qualify.

That isn't possible. The three consecutive number are assumed to be integers; the sum of three consecutive integers is always a multiple of 3 (try it out).

There are no such numbers. The smallest set of three consecutive composite numbers is {8, 9, 10} and the product of these numbers is 720.

Three consecutive odd numbers: 3, 5, 7

they are 29 31 33

5*6*7 = 210

3, 5 and 7

22*23*24 = 12144