(tan x - sin x)/(tan x sin x) = (tan x sin x)/(tan x + sin x)
[sin x/cos x) - sin x]/[(sin x/cos x)sin x] =? [(sin x/cos x)sin x]/[sin x/cos x) + sin x]
[(sin x - sin x cos x)/cos x]/(sin2 x/cos x) =? (sin2 x/cos x)/[(sin x + sin x cos x)/cos x)
(sin x - sin x cos x)/sin2 x =? sin2 x/(sin x + sin x cos x)
[sin x(1 - cos x)]/sin2 x =? sin2 x/[sin x(1 + cos x)
(1 - cos x)/sin x =? sin x/(1 + cos x)
(1 - cos x)/sin x =? [(sin x)(1 - cos x)]/[(1 + cos x)(1 - cos x)]
(1 - cos x)/sin x =? [(sin x)(1 - cos x)]/[1 - cos2 x)
(1 - cos x)/sin x =? [(sin x)(1 - cos x)]/[1 - (1 - sin2 x)]
(1 - cos x)/sin x =? [(sin x)(1 - cos x)]/sin2 x
(1 - cos x)/sin x = (1 - cos x)/sin x True
Cannot prove that 2 divided by 10 equals 2 because it is not true.
Because there is no way to define the divisors, the equations cannot be evaluated.
a0=(a-1\a-1)=a\a=1
It is extremely difficult to prove things which are not true.
You can't prove it, because it's usually not true.The only time it's true is when x=0 .
Cannot prove that 2 divided by 10 equals 2 because it is not true.
Because there is no way to define the divisors, the equations cannot be evaluated.
What divided by 7 equals 8? In other words, you have an unknown number (X), and then if you divide that X by 7 you get 8. Then what is that X? The equation to calculate what divided by 7 equals 8 is as follows: X/7 = 8 Where X is the answer. When we solve the equation by multiplying each side by 7, you get get: X = 56 Therefore, the answer to what divided by 7 equals 8 is 56.
You can't it equals 2. You can't it equals 2.
No you can not prove that 9 +10 = 21.
prove:E=mc2
No, but there is a way to prove that zero equals one.
Using faulty logic.
a0=(a-1\a-1)=a\a=1
Using a calculator
SAS
AAS (apex)